我创建了一个接收表，该表将存储用户的信息。但是这些值不会插入数据库中。 这是我与数据库和sql语句的连接，用于插入用户将要发布的值。
$host="localhost"; // Host name
$username="root"; // Mysql username
$password="l3tme1N@123"; // Mysql password
$db_name="shipping_pro"; // Database name
$tbl_name="receiver"; // Table name
// Connect to server and select database.
$con = mysql_connect("$host", "$username", "$password")or die("cannot
connect");
if(!$con){
die ('cannot connect to the server')
}
if (!mysql_select_db("$db_name", $con))
{
echo"no db selected";
}
if(isset($_POST['save']))
{
$name = $_POST['name'];
$cc = $_POST['cc'];
$sender = $_POST['sender-name'];
$address=$_POST['address'];
$tracker = $_POST['tracker'];
$code_phone = $_POST['code_phone'];
$phone = $_POST['phone'];
$code_phone1 = $_POST['code_phone1'];
$telefono = $_POST['telefono'];
$sql1="INSERT INTO 'receival' (name,idcard,sender-name,address,tracker,
receiver-telnum, sender-telnum) VALUES
('$name','$cc','$sender','$address', '$tracker', '$code_phone$phone',
'$code_phone1$telefono')";
$result = mysql_query($con,$sql1);
}
?>
html代码
这是我为接受用户输入而创建的表格。
我已经在这里和Google上查看了大多数解决方案，但仍然找不到任何解决方法
<form action="receive.php" method="post" class="form-horizontal" data-
parsley-validate novalidate >
<div class="form-group " id="gnombre">
<label for="office" class="col-sm-2 control-label">Name of Recipient</label>
<div class="col-sm-10">
<input type="text" class="form-control office" parsley-trigger="change"
required name="name" placeholder="Name of Recipient">
</div>
</div>
<div class="form-group " id="gnombre">
<label for="officer_name" class="col-sm-2 control-label"><?php echo $CEDULA;
?></label>
<div class="col-sm-10">
<input type="number" class="form-control officer_name" parsley-
trigger="change" required name="cc" placeholder="<?php echo $numbercedula; ?
>">
</div>
</div>
<div class="form-group " id="gnombre">
<label for="officer_name" class="col-sm-2 control-label">Sender</label>
<div class="col-sm-10">
<input type="text" class="form-control officer_name" iparsley-
trigger="change" required name="sender-name" placeholder="Name of Sender">
</div>
</div>
<div class="form-group" id="gapellido">
<label for="address" class="col-sm-2 control-
label"><?php echo $direccion; ?></label>
<div class="col-sm-10">
<input type="text" class="form-control address" parsley-trigger="change"
required name="address" placeholder="Receiver Address">
</div>
</div>
<div class="form-group" id="gapellido">
<label for="address" class="col-sm-2 control-label">Tracker Number</label>
<div class="col-sm-10">
<form name="form2" action="" method="">
<!--<strong><?php echo $codeproducto; ?></strong><br> -->
<input type="text" autofocus list="browsers" name="" autocomplete="off" class="form-control" required>
<datalist id="browsers">
<?php
$pa=mysql_query("SELECT tracking FROM courier
");
while($row=mysql_fetch_array($pa)){
echo '<option value="'.$row['tracking'].'">';
}
?>
</datalist>
</div>
</div>
<div class="form-group" id="ptelefonos">
<label for="address" class="col-sm-2 control-label"><?php echo $telefono; ?></label>
<div class="col-sm-4">
<select type="number" class="form-control ph_no" parsley-trigger="change" required name="code_phone" placeholder="<?php echo $telefonocustomer2; ?>">
<option data-countrycode="GH" value="233">Ghana (+233)</option>
</select>
</div>
<div class="col-sm-6">
<input type="number" class="form-control ph_no" parsley-trigger="change" required name="phone" placeholder="Receiver's Phone Number">
</div>
</div>
<div class="form-group" id="ptelefonos">
<label for="address" class="col-sm-2 control-label"><?php echo $telefono; ?></label>
<div class="col-sm-4">
<select type="number" class="form-control ph_no" parsley-trigger="change" required name="code_phone1" placeholder="Sender's phone Number">
<option data-countrycode="GH" value="233">Ghana (+233)</option>
</select>
</div>
<div class="col-sm-6">
<input type="number" class="form-control ph_no" parsley-trigger="change" required name="telefono" placeholder="Sender's phone Number">
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal"><i class="fa fa-times"></i>
<?php echo $cerrar; ?></button>
<input class="btn btn-success" name="save" type="submit" id="submit" value="Save">
</div>
</form>
答案 0 :(得分：0)
尝试使用此代码，您需要将“ receival”替换为receival：
$host="localhost"; // Host name
$username="root"; // Mysql username
$password="l3tme1N@123"; // Mysql password
$db_name="shipping_pro"; // Database name
$tbl_name="receiver"; // Table name
// Connect to server and select database.
$con = mysql_connect("$host", "$username", "$password")or die("cannot
connect");
if(!$con){
die ('cannot connect to the server')
}
if (!mysql_select_db("$db_name", $con))
{
echo"no db selected";
}
if(isset($_POST['save']))
{
$name = $_POST['name'];
$cc = $_POST['cc'];
$sender = $_POST['sender-name'];
$address=$_POST['address'];
$tracker = $_POST['tracker'];
$code_phone = $_POST['code_phone'];
$phone = $_POST['phone'];
$code_phone1 = $_POST['code_phone1'];
$telefono = $_POST['telefono'];
$sql1="INSERT INTO receival (name,idcard,sender-name,address,tracker,
receiver-telnum, sender-telnum) VALUES('$name','$cc','$sender','$address', '$tracker', '$code_phone$phone',
'$code_phone1$telefono')";
$result = mysql_query($con,$sql1);
}
?>
答案 1 :(得分：0)
已经在注释中指出，您必须对已准备好的语句使用mysqli_ *或PDO。因此，我将看看您最琐碎的错误（假设这是唯一的错误）
您的插入查询有很多错误：值未正确插入，并且表名用引号引起来。 更改为：
$sql1="INSERT INTO receival (name,idcard,sender-name,address,tracker,
receiver-telnum, sender-telnum) VALUES
('$name','$cc','$sender','$address', '$tracker', '$code_phone.$phone',
'$code_phone1.$telefono')";
这应该修复它并使插入工作正常。