正如标题中所述,我很难尝试制作一件看起来很简单的东西。这是一个简单的示例,更容易理解。
var reccords = {
1: {
1: [10, 'zorro'],
2: [25, 'ro']
},
2: {
1: [20, "dim"]
}
}
var time = 5;
reccords[3] = {
time: [2, 'michel']
}; //time isn't considered as a variable
document.getElementById("demo2").innerHTML = reccords[3]['time'][0];
document.getElementById("demo1").innerHTML = reccords[3][5][0]; //does not work, how to make it work?
<p id="demo1"></p>
<p id="demo2"></p>
答案 0 :(得分:1)
尝试以下使用[time]
设置time
的值,即5作为对象的属性。这样,在reccords[3]['time'][0]
的情况下,您需要使用reccords[3][time][0]
,因为records[3]
不具有time
属性。
var reccords = {1:{1:[10,'zorro'],2:[25,'ro']}, 2:{1:[20,"dim"]}}
var time=5;
reccords[3] = {[time]:[2, 'michel']}; //time isn't considered as a variable
document.getElementById("demo2").innerHTML = reccords[3][time][0];
document.getElementById("demo1").innerHTML = reccords[3][5][0];
<p id="demo1"></p>
<p id="demo2"></p>