Question

我正在创建一个页面，单击发布按钮，该页面将位于输入下方，并将输入数据存储到数据库中，但是遇到上述问题！我在下面共享我的代码

<script
  src="https://code.jquery.com/jquery-3.1.1.min.js"></script>
  <script>
  function get(){
      var input = $("#cmt").val();
      $.post('postToPage.php',{comment:input},function(output){
        $("#post-data").prepend(output+"<br><hr>")});

  }


      </script>
<div class="container"  style="margin-top:20px;">
    <div class="form-group">
      <form name="frm" >

      <input type="text" class="form-control" name="cmt" id="cmt" placeholder='Why So Empty!! Please Post Something'>
      <input class="btn btn-primary" type="button"  onclick="get();" value="Post">

      </form>
    </div>

    <br>
    <br>
<!--Here the post data will be visible-->
    <div id="post-data">

    </div>
</div>

postToPage.php文件

<?php 
require_once('db.php');
$cmt = $_POST['comment'];
$query = "INSERT INTO post (id,body) VALUES ('','$cmt')";
mysqli_query($conn,$query);
echo $cmt;
?>

数据库配置文件db.php

<?php

$conn = mysqli_connect("localhost","root","","signup_data");

?>

请显示错误。谢谢

Answer 1

尝试以下代码

 <script>
  function get(){

      var input = $("#cmt").val();
      $.ajax({
                        type: 'post',
                        url: 'postToPage.php',
                        data: {
                            comment: input,

                        },
                        success: function (response) {
                             document.getElementById("post-data").innerHTML = response;
                        }
                    });


  }


      </script>

未捕获的类型错误，$。post不是函数吗？

1 个答案: