Question

这是我的桌子

    idMission Event               Timestamp
    1         detectedBubbleOut 2018-05-26T12:53:43.000Z
    1         arrived               2018-05-26T13:58:57.000Z
    1         detectedInBuilding    2018-05-26T12:42:20.000Z
    1         detectedBubbleIn  2018-05-26T12:37:36.000Z
    1         detectedTimeOut       2018-05-26T12:52:17.000Z
    1         scanFulfilled     2018-05-26T12:41:26.000Z
    1         detectedBubbleIn  2018-05-26T12:37:22.000Z
    1         customerInteraction   2018-05-26T13:59:04.000Z
    1         scanFulfilled     2018-05-26T13:59:01.000Z
    1         delFulfilled      2018-05-26T12:48:30.000Z
    1         eventFulfilled        2018-05-26T12:48:30.000Z
    1         nextDelivery      2018-05-26T12:50:20.000Z
    1         customerInteraction   2018-05-26T12:48:18.000Z
    1         detectedOutBuilding   2018-05-26T12:49:21.000Z
    1         arrived               2018-05-26T12:40:09.000Z
    1         detectedTimeIn        2018-05-26T12:38:58.000Z
    2         nextDelivery          2018-05-27T12:50:20.000Z
    2         customerInteraction   2018-05-27T12:48:18.000Z
    2         detectedOutBuilding   2018-05-27T12:49:21.000Z
    2         arrived               2018-05-27T12:40:09.000Z
    2         detectedTimeIn        2018-05-27T12:38:58.000Z

有些事件与时间戳相关，这是事件发生的时间。我专注于事件“ arrived”和“ detectedTimeIn”，但事件“ detectedTimeIn”并不总是可用，因此我使用“ arrived”。我想要的只是根据特定事件获取时间戳。如果事件“ detectedTimeIn”存在，则获取其时间戳，如果不存在，则获取事件“到达”的时间戳。这是我到目前为止所取得的成就：

    select 
        event,
        stp."timestamp" as TimeIN
    from main_source_execevent_coop stp
    where event Coalesce('detectedTimeIn', 'arrived')

预期结果：

1         detectedTimeIn        2018-05-26T12:38:58.000Z
2         arrived               2018-05-27T12:40:09.000Z

但是我无法获得：检测到1个时间于2018-05-26T12：38：58.000Z

忽略“到达”行。有什么建议吗？

谢谢

Answer 1

如果您正在查看“下一个”或“上一个”事件，请使用lead() / lag()：

select t.*
from (select stp.*,
             lag(event) over (order by timestamp) as prev_event
      from main_source_execevent_coop stp
     ) stp
where event = 'detectedTimeIn' or
      (event = 'arrived' and next_event is distinct from 'detectedTimeIn');

Answer 2

尝试一下：

SELECT * FROM 
   (SELECT event,
    stp."timestamp" as TimeIN
FROM your_table
      WHERE event ='detectedTimeIn'
      LIMIT 1

    UNION ALL

    SELECT event,
    stp."timestamp" as TimeIN
FROM your_table
      WHERE event ='arrived'
      LIMIT 1) a
LIMIT 1

基于列值的抓取值

2 个答案: