Question

我的data.frame中的第一列由字符串组成，第二列是唯一键。

我想从每个字符串中提取第n个单词之后的所有单词，如果字符串中有<= n个单词，则提取整个字符串。

我的data.frame中有超过1万行，并且想知道是否除了使用for循环之外还有其他快速的方法？

谢谢。

Answer 1

以下内容如何：

# Generate some sample data
library(tidyverse)
df <- data.frame(
    one = c("Entries from row one", "Entries from row two", "Entries from row three"),
    two = runif(3))


# Define function to extract all words after the n=1 word 
# (or return the full string if n > # of words in string)
crop_string <- function(ss, n) {
    lapply(strsplit(as.character(ss), "\\s"), function(v)
        if (length(v) > n) paste(v[(n + 1):length(v)], collapse = " ")
        else paste(v, collapse = " "))
}

# Let's crop strings from column one by removing the first 3 words (n = 3)
n <- 3;
df %>%
    mutate(words_after_n = crop_string(one, n))
#                     one       two words_after_n
#1   Entries from row one 0.5120053           one
#2   Entries from row two 0.1873522           two
#3 Entries from row three 0.0725107         three


# If n > # of words, return the full string
n <- 10;
df %>%
    mutate(words_after_n = crop_string(one, n))
#                     one       two          words_after_n
#1   Entries from row one 0.9363278   Entries from row one
#2   Entries from row two 0.3024628   Entries from row two
#3 Entries from row three 0.6666226 Entries from row three

Answer 2

这里我使用nchar（），因此使您的数据已转换为字符。

as.character(YOUR_DATA)
as.character(sapply(YOUR_DATA,function(x,y){
if(nchar(x)>=y){
substr(x,y,nchar(x))  
}
else{x}
},y= nth_data_you_want))

汇总数据如下：
“ gene @ seq”
“ Cblb @ TAGTCCCGAAGGCATCCCGA”
“ Fbxo27 @ CCCACGTGTTCTCCGGCATC”

“ Fbxo11 @ GGAATATACGTCCACGAGAA”

“ Pwp1 @ GCCCGACCCAGGCACCGCCT”

我使用10作为第n个数据，结果是：

“ gene @ seq”
“ CCCGAAGGCATCCCGA”
“ CACGTGTTCTCCGGCATC”

“ AATATACGTCCACGAGAA”

“ GACCCAGGCACCGCCT”

如何从R中的字符串中提取第n个单词之后的所有单词？

2 个答案: