我希望程序执行的基本操作:
Aubio通过从麦克风输入的内容打印频率(音高)和音量(音量)
我要遍历字典,并根据输出的频率,打印与要输出样本频率的字典中哪个键匹配的颜色
我不断收到此错误:
回溯(最近通话最近): 在“ numpy.ndarray”和“ str”的实例之间不支持TypeError:“>”
任何人都可以帮助我吗?有问题的代码是 for 语句
import aubio
import numpy as num
import pyaudio
import sys
# Some constants for setting the PyAudio and the
# Aubio.
BUFFER_SIZE = 2048
CHANNELS = 1
FORMAT = pyaudio.paFloat32
METHOD = "default"
SAMPLE_RATE = 44100
HOP_SIZE = BUFFER_SIZE//2
PERIOD_SIZE_IN_FRAME = HOP_SIZE
index = 0
def main(args):
# Initiating PyAudio object.
pA = pyaudio.PyAudio()
# Open the microphone stream.
mic = pA.open(format=FORMAT, channels=CHANNELS,
rate=SAMPLE_RATE, input=True,
frames_per_buffer=PERIOD_SIZE_IN_FRAME)
# Initiating Aubio's pitch detection object.
pDetection = aubio.pitch(METHOD, BUFFER_SIZE,
HOP_SIZE, SAMPLE_RATE)
# Set unit.
pDetection.set_unit("Hz")
# Frequency under -40 dB will considered
# as a silence.
pDetection.set_silence(-40)
# Infinite loop!
while True:
# Always listening to the microphone.
data = mic.read(PERIOD_SIZE_IN_FRAME)
# Convert into number that Aubio understand.
samples = num.fromstring(data,
dtype=aubio.float_type)
# Finally get the pitch.
pitch = pDetection(samples)[0]
# Compute the energy (volume)
# of the current frame.
volume = num.sum(samples**2)/len(samples)
# Format the volume output so it only
# displays at most six numbers behind 0.
volume = "{:6f}".format(volume)
answer = pitch_detection(samples)
# Finally print the pitch and the volume.
print(str(pitch) + " " + str(volume) + (str(answer)))
def pitch_detection(samples):
colordict = {
(0.0, 13.99): "Red",
(14.00, 250.00): "Blue",
}
for index, key in enumerate(colordict, start=0):
if samples > colordict[key][0] and samples < colordict[key][1]:
return key
return "Not Found"
if __name__ == "__main__":
main(sys.argv)
答案 0 :(得分:1)
samples
是一个numpy数组。
colordict[key][0]
是一个字符(由于colordict[key]
是一个类似"Red"
的文本,因此[0]
将从字符串"R"
中获得第一个字符)
您的比较if samples > colordict[key][0] and samples < colordict[key][1]:
正在将numpy数组与一个char进行比较,但失败了。
现在,我不确定您真正想要的是什么。如果您的意思是key[0]
和key[1]
(要分别从键中获取每个值),则需要比较一个浮点数,而不是samples
(包含多个值-它是一个数组)还是迭代samples
进行比较?
答案 1 :(得分:0)
for index, key in enumerate(colordict):
if pitch > key[0] and pitch < key[1]:
return colordict[key]
最终修复它。谢谢大家<3