我有2个型号。
用户:
@Entity
public class User implements Serializable {
Long id;
String name;
List<Car> cars;
public User() {
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public List<Car> getCars() {
return cars;
}
public void setCars(List<Car> cars) {
this.cars = cars;
}
}
汽车:
@Entity
public class Car implements Serializable {
Long id;
String mark;
public Car() {
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getMark() {
return mark;
}
public void setMark(String mark) {
this.mark = mark;
}
}
映射fies:
用户:
<hibernate-mapping>
<class name="com.bontade.phone_book.mvc.spring.models.User" table="USERS">
<id name="id" type="java.lang.Long">
<column name="ID" />
<generator class="identity" />
</id>
<property name="name" not-null="true" length="100" type="java.lang.String">
<column name="NAME" />
</property>
<list name="cars" table="USER_CAR" cascade="all">
<key>
<column name="USER_ID" />
</key>
<list-index></list-index>
<many-to-many column="CAR_ID" class="com.bontade.phone_book.mvc.spring.models.Car" />
</list>
</class>
</hibernate-mapping>
汽车:
<hibernate-mapping>
<class name="com.bontade.phone_book.mvc.spring.models.Car" table="CARS">
<id name="id" type="java.lang.Long">
<column name="ID" />
<generator class="identity" />
</id>
<property name="mark" not-null="true" length="20" type="java.lang.String">
<column name="MARK" />
</property>
</class>
</hibernate-mapping>
HomePageController:
public class HomePageController extends AbstractController {
private UserDAO userDAO;
private CarDAO carDAO;
@Override
protected ModelAndView handleRequestInternal(HttpServletRequest request,
HttpServletResponse response) throws Exception {
Car markCar = new Car();
markCar.setId(null);
markCar.setMark("111");
carDAO.saveCar(markCar);
User mark = new User();
mark.setId(null);
mark.setName("mark");
List a = new ArrayList<Car>();
a.add(markCar);
mark.setCars(a);
userDAO.saveUser(mark);
List<User> users = userDAO.getAll();
System.out.println("==" + users.size() + "===");
System.out.println(users.get(0).getCars().get(0).getMark());
...
}
...
}
但是当我执行line:
时System.out.println(users.get(0).getCars().get(0).getMark());
我在跟踪堆栈跟踪时遇到错误:
Hibernate: select user0_.ID as ID0_, user0_.NAME as NAME0_ from USERS user0_
==1==
2011-02-23 17:35:10 org.apache.catalina.core.StandardWrapperValve invoke
SEVERE: Servlet.service() for servlet [dispatcher] in context with path [/PhoneBook] threw exception [Request processing failed; nested exception is org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: com.bontade.phone_book.mvc.spring.models.User.cars, no session or session was closed] with root cause
org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: com.bontade.phone_book.mvc.spring.models.User.cars, no session or session was closed
at org.hibernate.collection.AbstractPersistentCollection.throwLazyInitializationException(AbstractPersistentCollection.java:380)
at org.hibernate.collection.AbstractPersistentCollection.throwLazyInitializationExceptionIfNotConnected(AbstractPersistentCollection.java:372)
at org.hibernate.collection.AbstractPersistentCollection.readElementByIndex(AbstractPersistentCollection.java:173)
at org.hibernate.collection.PersistentList.get(PersistentList.java:293)
at com.bontade.phone_book.mvc.spring.controllers.HomePageController.handleRequestInternal(HomePageController.java:59)
at org.springframework.web.servlet.mvc.AbstractController.handleRequest(AbstractController.java:153)
at org.springframework.web.servlet.mvc.SimpleControllerHandlerAdapter.handle(SimpleControllerHandlerAdapter.java:48)
at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:875)
at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:807)
at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:571)
at org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:501)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:306)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.springframework.web.filter.CharacterEncodingFilter.doFilterInternal(CharacterEncodingFilter.java:96)
at org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:76)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:244)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:240)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:161)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:164)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:108)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:558)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:379)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:243)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:259)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:281)
at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908)
at java.lang.Thread.run(Thread.java:662)
我是否错误构造了映射文件,特别是多对多关系?
答案 0 :(得分:3)
默认情况下,Hibernate将延迟加载集合。换句话说,在绝对需要之前,它不会去数据库检索汽车列表。这意味着你的dao图层返回的对象在你尝试访问它之前不会初始化汽车列表。当您尝试访问它时,您不再在会话中,因此您将获得例外。
您可以通过在hibernate映射中设置lazy =“false”来显式禁用该列表属性的延迟提取,这将确保在从dao层返回之前填充整个属性。