使用Firebase的推荐系统

Question

我想在我的应用程序中添加引荐系统。我正在使用Firebase动态链接。但是当其他用户安装该应用程序时无法收听。如果有人使用动态链接安装该应用程序，则发件人将获得一些要点。是我生成短链接的代码。

public static Uri buildDeepLink( String product_name, int minVersion) {

    String DEEP_LINK_URL = null;
    FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
    String uid = user.getUid();
    String domain = "example.com";

    JSONObject json_data = new JSONObject();
    JSONObject json_parent = new JSONObject();

    try {
        json_data.put("useremail",product_name);
        json_parent.put("data",json_data);
        DEEP_LINK_URL = "https://example.com/?invitedby=" + product_name;
    } catch (JSONException e) {
        e.printStackTrace();
    }

    DynamicLink dynamicLink = FirebaseDynamicLinks.getInstance().createDynamicLink()
            .setLink(Uri.parse(DEEP_LINK_URL))
            .setDynamicLinkDomain(domain)
            .setAndroidParameters(new DynamicLink.AndroidParameters.Builder()
                    .setMinimumVersion(minVersion)
                    .build())
            .buildDynamicLink();
    return dynamicLink.getUri();
}

这是侦听的代码。但是此侦听器始终提供空的深层链接。

 FirebaseDynamicLinks.getInstance()
            .getDynamicLink(getIntent())
            .addOnSuccessListener(this, new OnSuccessListener<PendingDynamicLinkData>() {
                @Override
                public void onSuccess(PendingDynamicLinkData pendingDynamicLinkData) {
                    //Get dynamic link from result (may be null if no link is found)

                    Uri deepLink = null;
                    if (pendingDynamicLinkData != null) {
                        deepLink = pendingDynamicLinkData.getLink();
                    }

                    if (deepLink != null) {
                        String referrerUid = deepLink.getQueryParameter("invitedby");
                        Toast.makeText(getApplicationContext(),referrerUid,Toast.LENGTH_LONG).show();
                        sendReward(referrerUid);
                    }
                    //Here, Handle deep link. For example open the linked content.

                    //Display deep link in UI
                }
            })
            .addOnFailureListener(this, new OnFailureListener() {

                @Override
                public void onFailure(@NonNull Exception e) {
                }
            });