Question

尝试使用EditText过滤Listview，但是每次我在EditText上输入文本时，我的listview都将变为空白，并且不返回任何结果。我已经尝试了许多方法，而这似乎是最简单的实施方法。任何帮助将不胜感激！

在我的适配器上

public class AdapterTrilhos extends BaseAdapter {
private final Activity activity;

private LayoutInflater inflater;
private List<Trilhos> triList;
private ArrayList<Trilhos> arraylist=null;


public AdapterTrilhos(List<Trilhos> triList, Activity activity) {
    this.activity = activity;
    this.triList = triList;
    this.arraylist = new ArrayList<Trilhos>();
    this.arraylist.addAll(triList);

}


@Override
public int getCount() {
    return this.triList.size();
}

@Override
public Object getItem(int position) {
    return this.triList.get(position);
}

@Override
public long getItemId(int position) {
    return position;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {


    if (inflater == null)
        inflater = (LayoutInflater) activity
                .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    if (convertView == null)

            convertView = inflater.inflate(R.layout.dadoslista, null);

            TextView idtxt = (TextView) convertView.findViewById(R.id.txtid);

            TextView tittxt = (TextView) convertView.findViewById(R.id.txttit);

           // TextView usertxt = convertView.findViewById(R.id.txtuser);

            TextView diftxt = (TextView) convertView.findViewById(R.id.txtdif);
   RatingBar ratess= (RatingBar) convertView.findViewById(R.id.ratings);

            Trilhos t = triList.get(position);

            idtxt.setText(String.valueOf(t.getId()));
            tittxt.setText(t.getTitulo());
         //   usertxt.setText(String.valueOf(t.getId_user()));
            diftxt.setText(t.getDificuldade());
            ratess.setRating(t.getMedia());

        return convertView;
    }

public void filter(String charText) {
    charText = charText.toLowerCase(Locale.getDefault());
    triList.clear();
    if (charText.length() == 0) {
        triList.addAll(arraylist);
    } else {
        for (Trilhos cs : arraylist) {
            if (cs.getTitulo().toLowerCase(Locale.getDefault()).contains(charText)) {
                triList.add(cs);
            }
        }
    }
    notifyDataSetChanged();
}

} 以及我的活动

search.addTextChangedListener(new TextWatcher() {

        @Override
        public void onTextChanged(CharSequence cs, int start, int before, int count) {
            // TODO Auto-generated method stub
            int textlength = cs.length();

            String text = search.getText().toString().toLowerCase(Locale.getDefault());
            adapter.filter(text);
        }

        @Override
        public void beforeTextChanged(CharSequence s, int start, int count,
                                      int after) {
            // TODO Auto-generated method stub

        }

        @Override
        public void afterTextChanged(Editable s) {
            // TODO Auto-generated method stub

        }
    });

我打算做的是，当我在editText上输入文字时，它只会返回带有输入文字的结果

Answer 1

我认为您应该直接在活动中过滤列表，然后交换到新适配器：

search.addTextChangedListener(new TextWatcher() {

    @Override
    public void onTextChanged(CharSequence cs, int start, int before, int count) {
        int textlength = cs.length();

        String text = search.getText().toString().toLowerCase(Locale.getDefault());

        List<Trilhos> filteredList = yourFilterMethod(oldList, text); 

        mListView.setAdapter(new AdapterTrilhos(filteredList, this));

    }
});

private List<Trilhos> yourFilterMethod(List<object> list, String text)
{
    // some stuff that filter your list using text and returns the filtered one

    return filteredList;
}

Answer 2

尝试这个？

struct Example {
    var partOne: Int
    var partTwo: Int
    var partThree: Int
}

var one = Example(partOne: 10, partTwo: 11, partThree: 12)
var two = Example(partOne: 10, partTwo: 11, partThree: 12)

var arrayOfExamples = [one, two]

for i in 0...arrayOfExamples[0].partThree {
    print(i)
}

//once i = 12, then

for i in 0...arrayOfExamples[1].partThree {
    print(i)
}

使用edittext和自定义适配器过滤Json Listview

2 个答案: