Question

我编写了以下代码来计算输入文件sample.txt中包含一段文本的句子，单词和字符的数量。它在给出句子和单词的数量方面效果很好，但没有给出精确和正确的字符数（没有空格和标点符号）

lines,blanklines,sentences,words=0,0,0,0
num_chars=0

print '-'*50

try:
    filename = 'sample.txt'
    textf = open(filename,'r')c
except IOError:
    print 'cannot open file %s for reading' % filename
    import sys
    sys.exit(0)

for line in textf:
    print line
    lines += 1
    if line.startswith('\n'):
        blanklines += 1
    else:

    sentences += line.count('.')+ line.count ('!')+ line.count('?')

    tempwords = line.split(None)
    print tempwords 
    words += len(tempwords)


textf.close()

print '-'*50
print "Lines:", lines
print "blank lines:",blanklines
print "sentences:",sentences
print "words:",words

import nltk
import nltk.data
import nltk.tokenize

with open('sample.txt' , 'r') as f:
    for line in f:
        num_chars += len(line)

num_chars = num_chars - (words +1 )

pcount = 0
from nltk.tokenize import TreebankWordTokenizer
with open('sample.txt','r') as f1:
    for line in f1:
        #tokenised_words = nltk.tokenize.word_tokenize(line)
        tokenizer = TreebankWordTokenizer()
        tokenised_words = tokenizer.tokenize(line)
    for w in tokenised_words:
        if ((w=='.')|(w==';')|(w=='!')|(w=='?')):
            pcount = pcount + 1
print "pcount:",pcount
num_chars = num_chars - pcount
print "chars:",num_chars

pcount是标点符号的数量。有人可以建议我需要做出的更改，以便找出没有空格和标点符号的确切字符数吗？

Answer 1

import string

#
# Per-line counting functions
#
def countLines(ln):      return 1
def countBlankLines(ln): return 0 if ln.strip() else 1
def countWords(ln):      return len(ln.split())

def charCounter(validChars):
    vc = set(validChars)
    def counter(ln):
        return sum(1 for ch in ln if ch in vc)
    return counter
countSentences = charCounter('.!?')
countLetters   = charCounter(string.letters)
countPunct     = charCounter(string.punctuation)

#
# do counting
#
class FileStats(object):
    def __init__(self, countFns, labels=None):
        super(FileStats,self).__init__()
        self.fns    = countFns
        self.labels = labels if labels else [fn.__name__ for fn in countFns]
        self.reset()

    def reset(self):
        self.counts = [0]*len(self.fns)

    def doFile(self, fname):
        try:
            with open(fname) as inf:
                for line in inf:
                    for i,fn in enumerate(self.fns):
                        self.counts[i] += fn(line)
        except IOError:
            print('Could not open file {0} for reading'.format(fname))

    def __str__(self):
        return '\n'.join('{0:20} {1:>6}'.format(label, count) for label,count in zip(self.labels, self.counts))

fs = FileStats(
    (countLines, countBlankLines, countSentences, countWords, countLetters, countPunct),
    ("Lines",    "Blank Lines",   "Sentences",    "Words",    "Letters",    "Punctuation")
)
fs.doFile('sample.txt')
print(fs)

结果

Lines                   101
Blank Lines              12
Sentences                48
Words                   339
Letters                1604
Punctuation             455

Answer 2

您还可以使用正则表达式替换所有非字母数字字符，然后计算每行中的字符数。

Answer 3

你可以做的就是当你读取该行时，迭代它并增加字符数：

for character in line:
    if character.isalnum():
        num_chars += 1

P.S。您可能希望更改if语句条件以满足您的特定需求，例如，如果您想要计算$。

Answer 4

尝试计算单词的数量和句子的数量，并获得类似单词的概率，

from nltk.tokenize import word_tokenize
from nltk.tokenize import sent_tokenize


text_file = open("..//..//static//output.txt", "r")
lines = text_file.readlines()
x=0
tokenized_words = [word_tokenize(i) for i in lines]
for i in tokenized_words:

    print(i) #array contain with tokens
    print(str(len(i))) #word count

    for j in i:
        if j== 'words': #simple algo for count number of 'words' to be count
            x = x+1

tokenized_sents = [sent_tokenize(k) for k in lines]

for  k in tokenized_sents:
    print("Sentences"+str(k)) #array contain with sentences
    print("number of sentences "+str(len(k))) #number of sentences

print("number of word"+str(x))
print("Probability of 'word' in text file "+str(x/len(i)))

用于计算输入文件中的句子，单词和字符数的代码

4 个答案: