Question

我的图像的URL字符串除以“ |”我想要一个php函数，该函数读取字符串将图像分开，并用“，”将其分开，以使用wordpress画廊组件

http://xxxxxxxx/xxxxxxx/wp-content/uploads/2018/02/large-IMG_5367.jpg|http://xxxxxxxx/xxxxxxx/wp-content/uploads/2018/02/large-IMG_5376.jpg|http://xxxxxxxx/xxxxxxx/wp-content/uploads/2018/02/large-IMG_6324.jpg

我试图创建一个从字符串获取id的php短代码

   /* ---------------------------------------------------------------------------
 * Shortcode | get_id_from_string
* --------------------------------------------------------------------------- */


add_shortcode('get_id_from_string', 'function_get_id_from_string');
function function_get_id_from_string($atts) {
  global $wpdb;
  $return_value = '';

  $url_array = explode('|', $atts['urls']);

  foreach ($url_array as &$url) {
    $return_value .= $wpdb->get_col($wpdb->prepare("SELECT ID FROM $wpdb->posts WHERE guid='%s';", $url))[0] . ',';

  }

  return rtrim($return_value, ',');
}

但是它不起作用，有人已经做过类似的事情吗？

预先感谢

Answer 1

尝试以下鳕鱼，如果在数据库中找到URL，它将返回ID并添加$return_value变量。

add_shortcode('get_id_from_string', 'function_get_id_from_string');
function function_get_id_from_string($atts)
{
    global $wpdb;
    //$imagestr = "http://xxxxxxxx/xxxxxxx/wp-content/uploads/2018/02/large-IMG_5367.jpg|http://xxxxxxxx/xxxxxxx/wp-content/uploads/2018/02/large-IMG_5376.jpg|http://xxxxxxxx/xxxxxxx/wp-content/uploads/2018/02/large-IMG_6324.jpg";
    $imagestr = $atts['urls'];
    $url_array = explode("|", $imagestr);
    $return_value = [];
    foreach ($url_array as $url) {
        $query = $wpdb->prepare("SELECT ID FROM $wpdb->posts WHERE guid='%s'", $url);
        $result = $wpdb->get_col($wpdb->prepare($query, $url), ARRAY_A);
        if (!empty($result))
            $return_value[] = $result[0];
    }
    $images_ids = implode(",", $return_value);
    return ($images_ids);
}

从字符串php wordpress获取ID

1 个答案: