在Unix中将点分隔的单词格式化为带括号的单词

Question

我有以下一行：

val CLMLINEFilterdDF = CLMLINE.filter(CLMLINEDF.CLM_LINE_ENCNTR_CD.isin("N","NA")  
&& CLMLINEDF.CLM_LINE_STTS_CD.isin("PD","APRVD","PDZB","APRZB","VOID")  
&& CLMLINEDF.HLTH_SRVC_TYPE_CD.notEqual( "ADA"))

我需要将其设置为以下格式：

val CLMLINEFilterdDF = CLMLINE.filter(CLMLINEDF("CLM_LINE_ENCNTR_CD").isin("N","NA")  
&&  CLMLINEDF("CLM_LINE_STTS_CD").isin("PD","APRVD","PDZB", "APRZB","VOID")  
&&  CLMLINEDF("HLTH_SRVC_TYPE_CD").notEqual( "ADA"))

如何在Unix脚本/命令中实现它？

我已经通过使用sed进行了尝试：

string="val CLMLINEFilterdDF = 
CLMLINE.filter(CLMLINEDF.CLM_LINE_ENCNTR_CD.isin("N","NA")  
&& CLMLINEDF.CLM_LINE_STTS_CD.isin("PD","APRVD","PDZB","APRZB","VOID")  
&& CLMLINEDF.HLTH_SRVC_TYPE_CD.notEqual( "ADA"))"

echo $string | sed -r "s/CLMLINEDF\.(.*)CLMLINEDF\.(.*)CLMLINEDF\(.*)/CLMLINEDF("\1")("\2")("\2")/g"

但是它没有给出正确的结果

Answer 1

$ sed -E 's/(CLMLINEDF)\.([^.]+)/\1("\2")/g' ip.txt
val CLMLINEFilterdDF = CLMLINE.filter(CLMLINEDF("CLM_LINE_ENCNTR_CD").isin("N","NA")  
&& CLMLINEDF("CLM_LINE_STTS_CD").isin("PD","APRVD","PDZB","APRZB","VOID")  
&& CLMLINEDF("HLTH_SRVC_TYPE_CD").notEqual( "ADA"))

• 使用单引号，除非您需要双引号。参见Difference between single and double quotes in Bash
• (CLMLINEDF)\.([^.]+)匹配CLMLINEDF，后跟.（元字符必须转义以进行字面匹配），后跟非.字符
  • 另请参见Character Classes and Bracket Expressions的手册
• \1("\2")根据需要重新安排
• g替换所有此类匹配项