PHP-达到一定数量后递增数组
我对PHP数组有疑问。让我告诉你我的故事。
我有一个报告，称为库存承购。该报告的目的是查看某产品每天平均销售多少。
以下是计算：
(beginning inventory quantity + delivery quantity - ending inventory quantity) / (datediff(ending inventory quantity date - beginning inventory quantity date)))
但这是为期三周的库存：请查看屏幕截图：
正如您在屏幕截图中所看到的，我标记了第一个结果，然后是第二个。我还包括了结果，它旁边是公式。如果您不清楚屏幕截图，请问我，以便我帮助您理解我的复杂问题。
现在这是我的代码：
$index = 0;
foreach($result as $key => $value) {
$final_array[$key]['sales_group_code'] = $value['sales_group_code'];
$final_array[$key]['sales_office_code'] = $value['sales_office_code'];
$final_array[$key]['sales_district_code'] = $value['sales_district_code'];
$final_array[$key]['customer_code'] = $value['customer_code'];
$final_array[$key]['customer'] = $value['customer'];
$final_array[$key]['week_no'] = $value['week_no'];
$final_array[$key]['product'] = $value['product'];
$final_array[$key]['delivery_quantity'] = $value['delivery_quantity'];
$final_array[$key]['inventory_date'] = $value['inventory_date'];
$final_array[$key]['inventory_quantity'] = $value['inventory_quantity'];
$final_array[$key]['overall_count'] = $value['overall_count'];
$inventory_array[] = $value['inventory_quantity'];
$inventory_date_array[] = $value['inventory_date'];
if ($previous_product == $value['product']) {
$delivery_array[] = $value['delivery_quantity'];
if ($row_ctr > 2) {
$row_ctr = 0;
$inventory_ctr++;
array_shift($delivery_array);
}
$row_ctr++;
$final_delivery_array = array_slice($delivery_array, 0, 3);
for ($i = 0; $i < $index; $i++) {
if (array_key_exists($i, $final_delivery_array)) {
$total_delivery+= $final_delivery_array[$i];
$date1 = new DateTime(date('Y-m-d', strtotime($inventory_date_array[$inventory_date_ctr])));
$date2 = new DateTime(date('Y-m-d', strtotime($value['inventory_date'])));
$diff = $date2->diff($date1)->days;
if ($diff > 0) {
$offtake = ((($total_delivery + $inventory_array[$inventory_ctr]) - $value['inventory_quantity']) / $diff);
}
else {
$offtake = ((($total_delivery + $inventory_array[$inventory_ctr]) - $value['inventory_quantity']) / 1);
}
$final_array[$index]['days'] = $diff;
$final_array[$index]['offtake'] = number_format((float)$offtake, 2, '.', '');
$final_array[$index]['days_to_last'] = ($value['inventory_quantity'] / $offtake);
}
}
$total_delivery = 0;
}
else {
$final_array[$index]['days'] = 0;
$previous_product = $value['product'];
$final_array[$index]['offtake'] = 0;
$final_array[$index]['days_to_last'] = 0;
$total_delivery = 0;
}
$index++;
}
我会尝试解释我的代码：
我将所有交货和库存数量存储在一个阵列中。
我创建一个行计数器，最多计数3个。我计数3个，因为请记住我们有3周的移动结果。
如果行计数器达到3，我将取消设置交货和库存阵列的第一个元素。
现在我很好。我可以的一切正常。
更新：这是我的代码的结果：
Array
(
[0] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 10
[product] => ASSORTED CUPCAKES
[delivery_quantity] => 13.00
[inventory_date] => 2018-03-06
[inventory_quantity] => 4.08
[overall_count] => 144
[days] => 0
[offtake] => 0
[days_to_last] => 0
)
[1] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 11
[product] => ASSORTED CUPCAKES
[delivery_quantity] => 11.00
[inventory_date] => 2018-03-13
[inventory_quantity] => 15.50
[overall_count] => 144
[days] => 7
[offtake] => -0.06
[days_to_last] => -258.33333333333
)
[2] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 12
[product] => ASSORTED CUPCAKES
[delivery_quantity] => 7.00
[inventory_date] => 2018-03-18
[inventory_quantity] => 5.17
[overall_count] => 144
[days] => 12
[offtake] => 1.41
[days_to_last] => 3.6688350088705
)
[3] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 14
[product] => ASSORTED CUPCAKES
[delivery_quantity] => 12.00
[inventory_date] => 2018-04-01
[inventory_quantity] => 5.25
[overall_count] => 144
[days] => 26
[offtake] => 1.11
[days_to_last] => 4.7346514047867
)
[4] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 17
[product] => ASSORTED CUPCAKES
[delivery_quantity] => 9.00
[inventory_date] => 2018-04-23
[inventory_quantity] => 35.67
[overall_count] => 144
[days] => 48
[offtake] => 0.16
[days_to_last] => 218.66666666667
)
[5] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 20
[product] => ASSORTED CUPCAKES
[delivery_quantity] => 3.00
[inventory_date] => 2018-05-14
[inventory_quantity] => 17.67
[overall_count] => 144
[days] => 69
[offtake] => 0.37
[days_to_last] => 47.202090592334
)
[6] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 21
[product] => ASSORTED CUPCAKES
[delivery_quantity] => 9.00
[inventory_date] => 2018-05-22
[inventory_quantity] => 7.17
[overall_count] => 144
[days] => 77
[offtake] => 0.47
[days_to_last] => 15.196531791908
)
[7] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 24
[product] => ASSORTED CUPCAKES
[delivery_quantity] => 7.00
[inventory_date] => 2018-06-11
[inventory_quantity] => 10.58
[overall_count] => 144
[days] => 97
[offtake] => 0.19
[days_to_last] => 55.204948897257
)
[8] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 8
[product] => BROWNIES
[delivery_quantity] => 2.00
[inventory_date] => 2018-02-21
[inventory_quantity] => 4.33
[overall_count] => 144
[days] => 0
[offtake] => 0
[days_to_last] => 0
)
[9] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 10
[product] => BROWNIES
[delivery_quantity] => 3.00
[inventory_date] => 2018-03-06
[inventory_quantity] => 2.33
[overall_count] => 144
[days] => 0
[offtake] => 26.84
[days_to_last] => 0.086810730253353
)
[10] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 11
[product] => BROWNIES
[delivery_quantity] => 9.00
[inventory_date] => 2018-03-13
[inventory_quantity] => 3.92
[overall_count] => 144
[days] => 7
[offtake] => 3.61
[days_to_last] => 1.0867326732673
)
[11] => Array
(
[sales_group_code] => 01
[sales_office_code] => 013
[sales_district_code] => 1307
[customer_code] => BUD001
[customer] => 1307-873 PPCI-ANTIPOLO SAN JOSE POB
[week_no] => 12
[product] => BROWNIES
[delivery_quantity] => 3.00
[inventory_date] => 2018-03-18
[inventory_quantity] => 12.67
[overall_count] => 144
[days] => 12
[offtake] => 1.13
[days_to_last] => 11.19587628866
)
从我的代码结果中可以看到，days元素不断增长。事实并非如此。
这是我的问题：
在提供的公式中，我们必须获取开始库存日期数量和结束库存数量日期的日期差。
现在，当我完成三个星期的运行结果时，就会出现我的问题。如果我已经完成了三个星期的运行结果，就必须移至下一行，对吗？那将是我的下一个开始的清单。但是我的问题是我总是得到开始的库存日期。即使我已经搬到接下来的三个星期。 因此，您会想象到日期差异总是在增长，因为它总是从第一行开始。
现在是我的问题，如何将库存日期以及交货数量和库存数量一起移动。
我希望我能很好地解释它。如果零件不清楚，请问我，我会向您解释。我已经解决了一个月了。
非常感谢您对我的问题表现出兴趣。希望您能指导我或至少带领我去哪里看看。
谢谢。
更新。我将包含我的ms sql查询。
select c.SGrp as sales_group_code,
c.SOffc as sales_office_code,
c.SDst as sales_district_code,
a.customer_code,
case
when
c.CustAlias != '' then c.CustAlias
else c.CustNm end as customer,
a.product,
b.delivery_week,
b.delivery_quantity,
a.inventory_date,
a.inventory_week as week_no,
a.inventory_quantity,
overall_count = count(*) over()
from (select a.CustCode as customer_code,
c.ProdNm as product,
cast(a.DtRcv as date) as inventory_date,
datepart(wk, a.DtRcv) as inventory_week,
CAST(sum(CAST(b.Qty AS FLOAT)/ c.CaseDiv) AS decimal(18,2)) as inventory_quantity
from BigEMerchandiser.dbo.tbl_Inventory_H as a
inner join BigEMerchandiser.dbo.tbl_Inventory_D as b
on a.TransCtr = b.TransCtr
inner join BigEMasterData.dbo.tbl_Materials as c
on b.Material = c.ExtMatGrp
group by a.CustCode,
c.ProdNm,
cast(a.DtRcv as date),
datepart(wk, a.DtRcv)) as a
inner join (select a.Cust as customer_code,
a.ProdNm as product,
a.WkNum as delivery_week,
sum(a.EQCaseQty) as delivery_quantity
from BigESales.dbo.tbl_CurrentSales as a
group by a.Cust,
a.ProdNm,
a.WkNum) as b
on a.customer_code = b.customer_code
and a.inventory_week = b.delivery_week
and a.product = b.product
inner join BigEMasterData.dbo.tbl_Customers as c
on a.customer_code = c.CustCode
inner join BigEUsers.dbo.user_role_area as d
on c.SDst = d.area_id
inner join BigEUsers.dbo.users as e
on d.role_id = e.role_id
where ((datepart(wk, a.inventory_week) >= datepart(wk, @date_from) and datepart(wk, a.inventory_week) <= datepart(wk, @date_to))
or isnull(@date_from,'')='' OR isnull(@date_to,'')='')
and ((a.product= @product)
or (isnull(@product, '') = ''))
and ((REPLACE(REPLACE(a.customer_code, CHAR(13), ''), CHAR(10), '') = @customer_code)
or (isnull(@customer_code, '') = ''))
and (e.id = @user_id)
and e.is_active = 1
and b.delivery_quantity >= 0
order by a.customer_code,
a.product,
a.inventory_week
offset @start rows
fetch next @page_size rows only
0 个答案:
没有答案
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