我创建了以下查询，从本质上将商店合并为特定的组。这些组是CDJR，CDJRF，ANP和FARMER。这是我想到的最有效的查询方法。您知道更快，更少代码驱动的查询吗？我正在学习如何成为一个更高效的查询编写器，任何输入将不胜感激。请阅读查询下方的详细信息。请注意，为简单起见，我仅添加了4个商店代码。让我知道是否需要更多信息。
WITH CTE
AS
(
SELECT
COUNT(D.storecode) AS StoreCount,
D.storeid,
D.storename,
D.storecode,
D.start,
D.organizationid,
CASE
WHEN F.storefranchisetypeid IN (1, 2, 3, 4, 7, 25, 19, 20, 26, 29, 30) THEN 'CDJR'
WHEN F.storefranchisetypeid IN (21, 23, 28) THEN 'FARMER'
WHEN F.storefranchisetypeid = 22 THEN 'ANP'
END AS BrandGroup
FROM
store AS D
JOIN organization AS BO ON D.organizationid = BO.organizationid
JOIN franchises AS F ON D.storeid= F.storeid
JOIN franchisetype AS FT ON F.franchisetypeid = FT.franchisetypeid
WHERE
BO.countryid = 6 -- USA only.
AND D.end IS NULL -- Active stores.
AND FT.active IS TRUE
AND F.end IS NULL -- Active franchises.
AND D.franchised = 'F'
AND D.trainingtypeid = 1
AND D.storemarket = 'M'
AND D.storecodes IN (45660, 45733, 54816, 60739)
GROUP BY
D.storeid,
D.storename, -- Dealer name detailed.
D.storecode, -- Dealer code.
D.start,
D.organizationid,
CASE
WHEN F.storefranchisetypeid IN (1, 2, 3, 4, 7, 25, 19, 20, 26, 29, 30) THEN 'CDJR'
WHEN F.storefranchisetypeid IN (21, 23, 28) THEN 'FARMER'
WHEN F.storefranchisetypeid = 22 THEN 'ANP'
END
),
CTE2
AS
(
SELECT *
FROM
CTE
EXCEPT
SELECT *
FROM
CTE
WHERE
storecount <= 4
AND brandgroup = 'CDJR'
),
CTE3
AS
(
SELECT
'CDJRF' AS FranchiseGroup,
storeid,
storename,
storecode,
start,
organizationid
FROM
CTE2
GROUP BY
storeid,
storename,
storecode,
start,
organizationid
HAVING
COUNT(storecode) >= 2
UNION
SELECT
BrandGroup,
storeid,
storename,
storecode,
start,
organizationid
FROM
CTE2
WHERE
storecode NOT IN
(
SELECT
storecode
FROM
CTE2
GROUP BY
storecode
HAVING
COUNT(storecode) >= 2
)
)
SELECT *
FROM CTE3
结果：
特许集团StoreID; StoreName; StoreCode;开始; OrganizationID
“ CDJR”; 520;“帕克市场”;“ 05002”;“ 1954-11-24”; 1336
“农民”； 763；“乔·墨菲的农场”；“ 23355”；“ 1980-04-24”； 1579
“ ANP”; 80549;“ A＆P”;“ 69069”;“ 2011-04-25”; 283224
“ CDJRF”; 623;“ Kraggers”;“ 09733”;“ 1952-01-24”; 1439
在下面的第一个CTE中，我提取存储数据，对其进行计数，然后将类型ID最初分为3组，而不是分为4组。CTE的结果在CTE查询下方提供。
SELECT
COUNT(D.storecode) AS StoreCount,
D.storeid,
D.storename,
D.storecode,
D.start,
D.organizationid,
CASE
WHEN F.storefranchisetypeid IN (1, 2, 3, 4, 7, 25, 19, 20, 26, 29, 30) THEN 'CDJR'
WHEN F.storefranchisetypeid IN (21, 23, 28) THEN 'FARMER'
WHEN F.storefranchisetypeid = 22 THEN 'ANP'
END AS BrandGroup
FROM
store AS D
JOIN organization AS BO ON D.organizationid = BO.organizationid
JOIN franchises AS F ON D.storeid= F.storeid
JOIN franchisetype AS FT ON F.franchisetypeid = FT.franchisetypeid
WHERE
BO.countryid = 6 -- USA only.
AND D.end IS NULL -- Active stores.
AND FT.active IS TRUE
AND F.end IS NULL -- Active franchises.
AND D.franchised = 'F'
AND D.trainingtypeid = 1
AND D.storemarket = 'M'
AND D.storecodes IN (45660, 45733, 54816, 60739)
GROUP BY
D.storeid,
D.storename, -- Dealer name detailed.
D.storecode, -- Dealer code.
D.start,
D.organizationid,
CASE
WHEN F.storefranchisetypeid IN (1, 2, 3, 4, 7, 25, 19, 20, 26, 29, 30) THEN 'CDJR'
WHEN F.storefranchisetypeid IN (21, 23, 28) THEN 'FARMER'
WHEN F.storefranchisetypeid = 22 THEN 'ANP'
END
结果：
StoreCount; StoreID; StoreName; StoreCode;开始; OrganizationID；品牌集团
1; 80549;“ A＆P”;“ 69069”;“ 2011-04-25”; 283224;“ ANP”
2; 763;“ Kraggers”;“ 23355”;“ 1980-04-24”; 1579;“ CDJR”
1; 763;“ Kraggers”;“ 23355”;“ 1980-04-24”; 1579;“农民”
7; 623；“乔·墨菲的农场”；“ 09733”；“ 1952-01-24”； 1439；“ CDJR”
1; 623;“乔·墨菲的农场”;“ 09733”;“ 1952-01-24”; 1439;“农民”
6; 520;“帕克农场”;“ 05002”;“ 1954-11-24”; 1336;“ CDJR”
第二个CTE CTE2删除了不相关的CDRJ。结果在查询下方。
CTE2
AS
(
SELECT *
FROM
CTE
EXCEPT
SELECT *
FROM
CTE
WHERE
storecount <= 4
AND brandgroup = 'CDJR'
结果：
StoreCount; StoreID; StoreName; StoreCode;开始; OrganizationID；品牌集团
6; 520;“帕克农场”;“ 05002”;“ 1954-11-24”; 1336;“ CDJR”
1; 80549;“ A＆P”;“ 69069”;“ 2011-04- 25”; 283224;“ ANP”
1; 623;“乔·墨菲的农场”;“ 09733”;“ 1952-01-24”; 1439;“菲亚特”
7; 623；“乔·墨菲的农场”；“ 09733”；“ 1952-01-24”； 1439；“ CDJR”
1; 763;“ Kraggers”;“ 23355”;“ 1980-04-24”; 1579;“ FIAT”
最后一个CTE CTE3在我计算出CDRJF结果与其他组后将其结合在一起。所有结果都将导致页面顶部的第一组结果。
SELECT
'CDJRF' AS FranchiseGroup,
storeid,
storename,
storecode,
start,
organizationid
FROM
CTE2
GROUP BY
storeid,
storename,
storecode,
start,
organizationid
HAVING
COUNT(storecode) >= 2
UNION
SELECT
BrandGroup,
storeid,
storename,
storecode,
start,
organizationid
FROM
CTE2
WHERE
storecode NOT IN
(
SELECT
storecode
FROM
CTE2
GROUP BY
storecode
HAVING
COUNT(storecode) >= 2
)
答案 0 :(得分：1)
好
您的查询格式正确且可读性强。
您意识到它效率不高。
不好
主要问题在于简化逻辑。这未经测试（请参阅坏点＃1），但可能会让您了解如何清除它。
SELECT DISTINCT *
FROM ( SELECT CASE WHEN COUNT(storeCode) OVER
( PARTITION BY storeid,
storename,
storecode,
start,
organizationid
) >= 2 THEN 'CDJRF'
ELSE BandGroup
END,
storeid,
storename,
storecode,
start,
organizationid
FROM (
SELECT
COUNT(D.storecode) AS StoreCount,
D.storeid,
D.storename,
D.storecode,
D.start,
D.organizationid,
F.BrandGroup
FROM
store AS D
JOIN organization AS BO ON D.organizationid = BO.organizationid
JOIN (SELECT store_id,
CASE
WHEN F.storefranchisetypeid IN (1, 2, 3, 4, 7, 25, 19, 20, 26, 29, 30) THEN 'CDJR'
WHEN F.storefranchisetypeid IN (21, 23, 28) THEN 'FARMER'
WHEN F.storefranchisetypeid = 22 THEN 'ANP'
END AS BrandGroup,
end
FROM franchises
) F
ON D.storeid= F.storeid
JOIN franchisetype AS FT ON F.franchisetypeid = FT.franchisetypeid
WHERE
BO.countryid = 6 -- USA only.
AND D.end IS NULL -- Active stores.
AND FT.active IS TRUE
AND F.end IS NULL -- Active franchises.
AND D.franchised = 'F'
AND D.trainingtypeid = 1
AND D.storemarket = 'M'
AND D.storecodes IN (45660, 45733, 54816, 60739)
GROUP BY
D.storeid,
D.storename, -- Dealer name detailed.
D.storecode, -- Dealer code.
D.start,
D.organizationid,
F.BrandGroup
) CTE
WHERE storeCount > 4
OR bandGroup <> 'CDJR'
) SUB;