Question

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错误是：

import math
def nthroot(x,n):
    c=math.pow(x,1/n)
    return(c)

a=float(input("enter the value of x"))
b=float(input("enter the value of n"))
d=nthroot(c)
print (c)

Answer 1

问题是variable scope。 c在函数外部不存在

您可能想要尝试为函数提供正确的参数，尽管如果您确实有一个c变量，则会得到一个不同的错误。

import math
def nthroot(x,n):
    return math.pow(x,1/n)

a=float(input("enter the value of x"))
b=float(input("enter the value of n"))

d=nthroot(a, b)  # See here
print(d)

如果将“ x”输入的值分配给名为x的实际变量也可能有帮助，以便您了解其用途是什么

Answer 2

由于您创建了一个带有两个参数的函数，因此在调用它时应该传递2个参数。您的代码应类似于-

import math

def nthroot(x,n):
    c=math.pow(x,1/n)
    return(c)
a=float(input("enter the value of x"))
b=float(input("enter the value of n"))
d=nthroot(a,b)
print (d)

现在，我们正在将从用户获取的两个值传递给函数（此处为a和b）。该函数正在计算结果，将结果存储在c中，然后返回c。我们将此结果存储在d中。最后我们要打印d。

在python 3.4的全局部分中的main函数中调用函数

2 个答案: