Question

我想将参数从asp.net传递到我的存储过程。这些参数将是从下拉列表中选择的值，然后从存储过程中获取数据，并在用户单击网页上的“提交”按钮时显示在asp.net的Gridview中。当我单击提交按钮时，GridView不会弹出。我现在坚持了一段时间。当我尝试调试它时，Fill方法弹出一个异常，提示我需要传递参数。异常复制到下面。

System.Data.SqlClient.SqlException：'过程或函数'Submit'需要未提供的参数'@Address'。'

下面是我的存储过程

USE [Database]
GO

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
ALTER procedure [Submit]
@Address varchar(12),
@Number varchar(5),
@Name varchar(24),
@Type varchar(3)
as 
begin
    select a.*, b.*
    from Employee as a
    inner join Department as b
    on a.Number = b.Number
    where a.Address = @Address and a.Number = @Number and a.name = @Name and b.Type = @Type 
end

下面是我的.cs代码

 protected void Button1_Click1(object sender, EventArgs e)
        {
            con.Open();
            string s = "Submit";
            SqlCommand cmd = new SqlCommand();
            cmd.CommandType = CommandType.StoredProcedure;
            cmd.CommandText = "Submit";
            cmd.Parameters.Add("@Address", SqlDbType.VarChar).Value = DropDownList5.SelectedItem.Value;
            cmd.Parameters.Add("@Number", SqlDbType.VarChar).Value = DropDownList2.SelectedItem.Value;
            cmd.Parameters.Add("@Name", SqlDbType.VarChar).Value = DropDownList3.SelectedItem.Value;
            cmd.Parameters.Add("@Type", SqlDbType.VarChar).Value = DropDownList4.SelectedItem.Value;
            SqlDataAdapter da = new SqlDataAdapter(s, con);
            DataSet ds = new DataSet();
            da.Fill(ds);

            GridView1.DataSource = ds;
            GridView1.DataBind();
            con.Close();
        }

Answer 1

您仅使用字符串s而不是SqlCommand cmd创建DataAdapter：

SqlDataAdapter da = new SqlDataAdapter(s, con);

Create it with the command instead.

Answer 2

尝试一下

DataTable dt = new DataTable();
using(var reader = cmd.ExecuteReader()) {
  dt.Load(reader);
}

GridView1.DataSource=dt;
GridView1.Databind():

将参数从asp.net传递到存储过程，并在GridView上显示结果

2 个答案: