我的问题是关于我在24小时格式下使用以下代码的日期和时间,但在这里我需要将格式更改为12小时。 请帮我解决这个问题。
$(document).ready(function() {
// Making 2 variable month and day
var monthNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var dayNames = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]
// make single object
var newDate = new Date();
// make current time
newDate.setDate(newDate.getDate());
// setting date and time
$('#Date').html(dayNames[newDate.getDay()] + " " + newDate.getDate() + ' ' + monthNames[newDate.getMonth()] + ' ' + newDate.getFullYear());
setInterval(function() {
// Create a newDate() object and extract the seconds of the current time on the visitor's
var seconds = new Date().getSeconds();
// Add a leading zero to seconds value
$("#sec").html((seconds < 10 ? "0" : "") + seconds);
}, 1000);
setInterval(function() {
// Create a newDate() object and extract the minutes of the current time on the visitor's
var minutes = new Date().getMinutes();
// Add a leading zero to the minutes value
$("#min").html((minutes < 10 ? "0" : "") + minutes);
}, 1000);
setInterval(function() {
// Create a newDate() object and extract the hours of the current time on the visitor's
var hours = new Date().getHours();
// Add a leading zero to the hours value
$("#hours").html((hours < 10 ? "0" : "") + hours);
}, 1000);
});
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
<div class="clock">
<div id="Date"></div>
<ul>
<li id="hours"></li>
<li id="point">:</li>
<li id="min"></li>
<li id="point">:</li>
<li id="sec"></li>
</ul>
</div>
&#13;
答案 0 :(得分:0)
使用("0"+hours%12).slice(-2)
做两位数12小时格式并使用(小时/ 12 == 0)来获取上午/下午:
$(document).ready(function() {
// Making 2 variable month and day
var monthNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var dayNames = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]
// make single object
var newDate = new Date();
// make current time
newDate.setDate(newDate.getDate());
// setting date and time
$('#Date').html(dayNames[newDate.getDay()] + " " + newDate.getDate() + ' ' + monthNames[newDate.getMonth()] + ' ' + newDate.getFullYear());
setInterval(function() {
// Create a newDate() object and extract the seconds of the current time on the visitor's
var seconds = new Date().getSeconds();
// Add a leading zero to seconds value
$("#sec").html((seconds < 10 ? "0" : "") + seconds);
}, 1000);
setInterval(function() {
// Create a newDate() object and extract the minutes of the current time on the visitor's
var minutes = new Date().getMinutes();
// Add a leading zero to the minutes value
$("#min").html((minutes < 10 ? "0" : "") + minutes);
}, 1000);
setInterval(function() {
// Create a newDate() object and extract the hours of the current time on the visitor's
var hours = new Date().getHours();
// Add a leading zero to the hours value
$("#hours").html(("0"+hours%12).slice(-2) + " " + ((hours/12 == 0)?"AM":"PM"));
}, 1000);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
<div class="clock">
<div id="Date"></div>
<ul>
<li id="hours"></li>
<li id="point">:</li>
<li id="min"></li>
<li id="point">:</li>
<li id="sec"></li>
</ul>
</div>
答案 1 :(得分:0)
使用此方法。
function ampmFormat(date) {
var hours = date.getHours();
var minutes = date.getMinutes();
var ampm = hours >= 12 ? 'pm' : 'am';
hours = hours % 12;
hours = hours ? hours : 12;
minutes = minutes < 10 ? '0'+minutes : minutes;
var strTime = hours + ':' + minutes + ' ' + ampm;
return strTime;
}
然后你可以添加日,月和年。
答案 2 :(得分:0)
在将当前小时分配为小时var。
后添加以下代码public void onCreate(Bundle arguments) {
MultiDex.install(getTargetContext());
super.onCreate(arguments);
}
将此行添加到html
var timing = hours >= 12 ? 'PM' : 'AM';
hours %= 12;
if(hours == 0)
hours = 12;
$("#ampm").html(timing);
更新代码 -
<li id="ampm"></li>
$(document).ready(function() {
// Making 2 variable month and day
var monthNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var dayNames = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]
// make single object
var newDate = new Date();
// make current time
newDate.setDate(newDate.getDate());
// setting date and time
$('#Date').html(dayNames[newDate.getDay()] + " " + newDate.getDate() + ' ' + monthNames[newDate.getMonth()] + ' ' + newDate.getFullYear());
setInterval(function() {
// Create a newDate() object and extract the seconds of the current time on the visitor's
var seconds = new Date().getSeconds();
// Add a leading zero to seconds value
$("#sec").html((seconds < 10 ? "0" : "") + seconds);
}, 1000);
setInterval(function() {
// Create a newDate() object and extract the minutes of the current time on the visitor's
var minutes = new Date().getMinutes();
// Add a leading zero to the minutes value
$("#min").html((minutes < 10 ? "0" : "") + minutes);
}, 1000);
setInterval(function() {
// Create a newDate() object and extract the hours of the current time on the visitor's
var hours = new Date().getHours();
var timing = hours >= 12 ? 'PM' : 'AM';
hours %= 12;
if(hours == 0)
hours = 12;
$("#ampm").html(timing);
// Add a leading zero to the hours value
$("#hours").html((hours < 10 ? "0" : "") + hours);
}, 1000);
});
答案 3 :(得分:-1)
您可以手动执行此操作。
If ( hours > 12){
hours = hours % 12;
}
else{
hours = hours;
}
您还可以添加一个字符串,
var ampm = am;
If ( hours > 12){
hours = hours % 12;
ampm = pm;
}
else{
hours = hours;
ampm = am;
}
或布尔或其他...... 我希望,这很有用