Question

我有一个项目，包含一些子项目和许多依赖项，一个子项目将拥有大多数开发（app）并生成完整的jar需要时间。所以我想将胖子一代分成两个罐子：

deps a fat-jar
app a lean-jar

我希望创建一个deps项目，如：

lazy val deps = (project in file("deps"))
 .settings(
   libraryDependencies ++= commonDependencies,
   assemblyJarName in assembly := "deps.jar",
   assemblyMergeStrategy in assembly := {
     case m if m.toLowerCase.endsWith("manifest.mf") => MergeStrategy.discard
     case m if m.toLowerCase.matches("meta-inf.*\\.sf$") => MergeStrategy.discard
     case m if m.toLowerCase.startsWith("meta-inf/services/") => MergeStrategy.filterDistinctLines
     case m if m.toLowerCase.endsWith(".dct") => MergeStrategy.first
     case "reference.conf" => MergeStrategy.concat
     case _ => MergeStrategy.first
   }
).dependsOn(
   measurement,
   streaming,
   domain
)

和我的应用项目如：

lazy val app = (project in file("my-app"))
  .settings(clientEventSettings)
  .settings(noPublishSettings)
  .settings(
    assemblyJarName in assembly := "my-app.jar",
    assemblyMergeStrategy in assembly := {
      case m if m.toLowerCase.endsWith("manifest.mf") => MergeStrategy.discard
      case m if m.toLowerCase.matches("meta-inf.*\\.sf$") => MergeStrategy.discard
      case m if m.toLowerCase.startsWith("meta-inf/services/") => MergeStrategy.filterDistinctLines
      case m if m.toLowerCase.endsWith(".dct") => MergeStrategy.first
      case "reference.conf" => MergeStrategy.concat
      case _ => MergeStrategy.first
    })
  .dependsOn(  //<- but do not package??
    measurement,
    streaming,
    messagingDomain,
    messagingKafkaToolkit,
    domain,
    analyticsWebtrekk,
    commons
  )

编译式my-app项目依赖于其他子项目（deps），但它应该是范围provided，因为我不希望它由sbt-assembly打包。

我将尝试使用libraryDependencies，但我认为这意味着克隆commonDependencies，所有这些都使用范围provided。

Answer 1

sbt-assembly的readme提供了答案：在此部分：Splitting your project and deps JARs

assemblyOption in assembly := (assemblyOption in assembly).value.copy(includeScala = false, includeDependency = false)

sbt-assembly排除dependsOn依赖项

1 个答案: