Question

我在变量

中获得了$id=2的ID

像： $ count_id = $请求 - ＆GT;获得（ 'count_id'）;

从一个函数我得到array如下所示：像：$结果= get_experiance（）;

    [0] => stdClass Object
        (
            [id] => 1
            [A] => a
            [B] => b
            [C] => c
            [D] => d
        )

    [1] => stdClass Object
        (
            [id] => 2
            [A] => w
            [B] => s
            [C] => d
            [D] => a
        )

    [2] => stdClass Object
        (
            [id] => 3
            [A] => r
            [B] => e
            [C] => f
            [D] => v
        )

我的问题是，当我得到$id=2中的值时，结果应该是这样的：

[0] => stdClass Object
        (
            [id] => 1
            [A] => a
            [B] => b
            [C] => c
            [D] => d
        )
[1] => stdClass Object
        (
            [id] => 3
            [A] => r
            [B] => e
            [C] => f
            [D] => v
        )

表示我想根据id删除get数组中的记录。我怎样才能实现这一点，谁能有最简单的方法？

Answer 1

您可以使用array_filter。如果您不想保留现有密钥，也可以使用array_values。

$arr = your array
$toRemove = "2";
$result = array_filter($arr, function($o) use ($toRemove){
    return $toRemove != $o->id;
});

echo "<pre>";
print_r( $result );
echo "</pre>";

这将返回：

Array
(
    [0] => stdClass Object
        (
            [id] => 1
            [A] => a
            [B] => b
            [C] => c
            [D] => d
        )

    [2] => stdClass Object
        (
            [id] => 3
            [A] => r
            [B] => e
            [C] => f
            [D] => v
        )

)

如果您不想要新变量，可以将数组覆盖为

$arr = array_filter($arr, function($o) use ($toRemove){
    return $toRemove != $o->id;
});

文档：array_filter()，array_values()

Answer 2

你可以这样做：

未设置（$阵列[$ ID]）;

$array是数组的所有元素都包含

的主要变量

$id是索引

删除特定id的数组元素

2 个答案: