Question

有一个用于创建表格的脚本。

create table #test_for_TRANSPOSE (id int, vol char(10), su int)

declare @num int 

set @num = 1

while @num <=50

begin

    insert into #test_for_TRANSPOSE (id, vol, su)

         values (@num, (select PATIENTS01.passport_data
           from  PATIENTS01                                                         
          where id_patients = @num),
                @num)                                                
        set @num = @num +1
   end

如何在行中传输列？

我试图这样做，但它不起作用：

create table #table_after_TRANSPOSE（new_vol varchar（15））

声明@num_transp int 声明@vol_transp char（15）声明@count_rows int 声明@column_name char（15）

设置@num_transp = 1 设置@count_rows =（从#test_for_TRANSPOSE中选择count（id））

而@num_transp＆lt; = @count_rows 开始设置@column_name ='column'+ @num_transp alter table #table_after_TRANSPOSE add @column_name char（10）插入#table_after_TRANSPOSE（@column_name）值（（选择＃test_for_TRANSPOSE.id 来自#test_for_TRANSPOSE 其中#test_for_TRANSPOSE.id = @num_transp），（选择＃test_for_TRANSPOSE.vol 来自#test_for_TRANSPOSE 其中#test_for_TRANSPOSE.id = @num_transp
））设置@num_transp = @num_transp + 1 端

在行中传输列

0 个答案: