Question

select *
  from (select debit
          from tblarpayments a
         where     paymenttype = 6
               and credit = 0
               and checkid = 522
        union
        select credit
          from tblarpayments b
         where     paymenttype = 6
               and debit = 0
               and checkid = 522
        union
        select debit
          from tblarpayments c
         where     ref# like 'A/R%'
               and checkid = 522
        union
        select credit
          from tblarpayments d
         where     debit = 0
               and paymenttype = 2
               and checkid = 522
        union
        select debit
          from tblarpayments e
         where     credit = 0
               and ref# not like 'A/R%'
               and checkid = 522)
| |   DEBIT   |
|1| 10.0000   |
|2| 240.0000  |
|3| 250.0000  |
|4| 11540.0000|

我希望它排成一排喜欢这个

 | |DEBIT     |CREDIT|DEBIT1 |CREDIT1 |DEBIT2  |
 |1|11540.0000|      |10.0000|250.0000|240.0000|

损失增值委员会信贷债务在第二个单元格中，Credit在checkid = 522 debit = 0时没有值coz = 0 paymenttype = 6没有信用值它为null。全部在一行如何解决？我尝试了很多东西，但我无法理解。

Answer 1

假设您的每一行返回不超过一行，那么这对您有用：

select t1.debit as LOSS
       , t2.credit as GAIN 
       , t3.debit as COMMISSION 
       , t4.credit as CREDIT 
       , t5.debit as DEBIT   
from ( 
    select *
    from tblarpayments a
    where  checkid = 522
    and paymenttype = 6
    and credit = 0
) t1
left outer join ( 
    select *
    from tblarpayments a
    where  checkid = 522
    and  paymenttype = 6
    and debit = 0
) t2 on t1.checkid = t2.checkid
left outer join ( 
    select *
    from tblarpayments a
    where  checkid = 522
    and ref# like 'A/R%'
) t3 on t1.checkid = t3.checkid
left  outer join ( 
    select *
    from tblarpayments a
    where  checkid = 522
    and debit = 0
    and paymenttype = 2
) t4 on t1.checkid = t4.checkid
left outer join ( 
    select *
    from tblarpayments a
    where  checkid = 522
    and credit = 0
    and ref# not like 'A/R%'
) t5 on t1.checkid = t5.checkid

我假设你总是有一个LOSS记录但你可能没有所有记录（你的图像没有显示GAIN的值），我使用了LEFT OUTER JOIN。但是，FULL OUTER JOIN可能更合适：您知道您的数据而我不知道。或者，如果您可以保证每个子查询始终都有记录，那么您应该使用INNER JOIN。

请注意，如果任何子查询确实返回多行，您将获得产品，因此您必须相应地调整过滤器。

编写此查询可能有更多表现方式。但是，如果没有实际的表结构和代表性数据，那么我将编写多少推测性代码是有限制的。

Answer 2

假设每个条件都有一个匹配行，那么您可以在单个表扫描中执行此操作：

SQL Fiddle

Oracle 11g R2架构设置：

CREATE TABLE tblarpayments ( paymenttype, credit, debit, ref#, checkid ) AS
SELECT 6, 0, 123, NULL, 522 FROM DUAL UNION ALL
SELECT 6, 456, 0, NULL, 522 FROM DUAL UNION ALL
SELECT 6, NULL, 789, 'A/R', 522 FROM DUAL UNION ALL
SELECT 2, 111, 0, NULL, 522 FROM DUAL UNION ALL
SELECT 3, 0, 222, 'X/Y', 522 FROM DUAL;

查询1 ：

SELECT MAX( CASE WHEN ( paymenttype, credit ) IN ( ( 6, 0 ) ) THEN debit  END ) AS debit,
       MAX( CASE WHEN ( paymenttype, debit  ) IN ( ( 6, 0 ) ) THEN credit END ) AS credit,
       MAX( CASE WHEN ref# LIKE 'A/R%' THEN debit END ) AS debit1,
       MAX( CASE WHEN ( paymenttype, debit  ) IN ( ( 2, 0 ) ) THEN credit END ) AS credit1,
       MAX( CASE WHEN ref# NOT LIKE 'A/R%' AND credit = 0 THEN debit END ) AS debit2
FROM   tblarpayments
WHERE  (  ( paymenttype, credit ) IN ( ( 6, 0 ) )
       OR ( paymenttype, debit  ) IN ( ( 6, 0 ), ( 2, 0 ) )
       OR ref# LIKE 'A/R%'
       OR ( ref# NOT LIKE 'A/R%' AND credit = 0 )
       )
AND    checkid = 522

<强> Results ：

| DEBIT | CREDIT | DEBIT1 | CREDIT1 | DEBIT2 |
|-------|--------|--------|---------|--------|
|   123 |    456 |    789 |     111 |    222 |

如何在使用union之后拆分列

2 个答案: