设置多个配置文件的弹簧配置

Question

我的应用配置文件application.yml中有多个配置文件，如下例所示：

spring:
  application:
    name: my-super-app
database:
  secret: "default secret"
this:
  that: "default value..."

---

spring:
  profiles: staging


---

spring:
  profiles: qa
database:
  secret: "foo bar"

---

spring:
  profiles: playground
database:
  secret: "foo bar"

---

spring:
  profiles: production
database:
  secret: "foo bar"

很明显，我为database.secret，qa和playground配置文件冗余设置production配置，staging除外。有没有办法为这三个配置文件设置一次，对配置文件进行分组或从基本配置文件继承？

Answer 1

您可以将逗号分隔列表（qa,playground,production）组合在一起，如下所示：

spring:
  application:
    name: my-super-app
common-secret: "foo bar"
database:
  secret: "default secret"
this:
  that: "default value..."

---

spring:
  profiles: staging


---

spring:
  profiles: qa

---

spring:
  profiles: playground

---

spring:
  profiles: production

---

spring:
  profiles: qa,playground,production
database:
    secret: "foo bar"

或者你可以设置一个“共享变量”，如下所示：

spring:
  application:
    name: my-super-app
common-secret: "foo bar"
database:
  secret: "default secret"
this:
  that: "default value..."

---

spring:
  profiles: staging


---

spring:
  profiles: qa
database:
  secret: ${common-secret}

---

spring:
  profiles: playground
database:
  secret: ${common-secret}

---

spring:
  profiles: production
database:
    secret: ${common-secret}