Question

我写的如下。但是如何使它更有效率。需要建议!!

For example, given:
      X = 10
      Y = 85
      D = 30

Y是目标，D是跳跃计数，X是当前位置。

function solution(X, Y, D) {

   for(var i =1; X<=Y; i++){
       X = X+D;
       if( X >= Y ){
           return i;
       }
   }
}

上面的代码工作正常，但如何有效地编写？

提前致谢！

Answer 1

你不需要模拟跳跃，你可以使用数学：

<!--php to upload csv file not working as written below-->  
<?php  

    include("DBconnection.php");

$sql= "LOAD DATA LOCAL INFILE 'kb-listings.csv'
    INTO TABLE `listings-table`
    FIELDS TERMINATED BY ','    OPTIONALLY ENCLOSED BY '\"'
    LINES TERMINATED BY '\r\n'
    (MLS, STATUS, ENTRY, SUB, ADDRESS, ZIP, BEDS, BATHS, HBATHS, SQFT-LIV, LOT-SQFT, ORIG-LP, LIST-PRICE, POOL, DOM, SALE-PRICE, M-FEE, TAXES, CLOSING, VIEW, UNIT-VIEW, OFFICE, YEAR-BUILT, GARAGE, PARK, TYPE, WF, AMEN, REMARKS)";


    if($result =mysqli_query($conn,$sql)){echo "success";}
    else 
        echo "failure";
    mysqli_close($conn);

    ?>

编辑：根据Patrick Robert的建议更新(X >= Y) ? 1 : Math.ceil((Y-X)/D)。

Answer 2

基于问题（所需的最小跳数），据我所知，当x == y应为0步时，则：

Math.ceil(Math.abs((Y-X)/D))

当<0和/或X <0

时，

起作用

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