最新记录和总结SQL

Question

我正在为这个问题寻找解决方案。

表：

我想要此输出（根据最大交易ID显示最新等级）

Answer 1

你可以这样做：

select *, sum(select sum(t1.poin)
              from table t1
              where t1.member_id = t.member_id
             ) as poin,
          sum(select sum(t1.freq)
              from table t1
              where t1.member_id = t.member_id
             ) as freq
from table t
where trans_id = (select t1.trans_id
                  from table t1
                  where t1.member_id = t.member_id
                  order by t1.trans_id desc
                  fetch first 1 rows only
                 );

大多数 DBMS 都支持fetch first 1 rows only方法。

如果您正在使用SQL Server，那么您可以直接将其表达为：

select t.member_id, tt.*
from (select *, row_number() over (partition by member_id order by trans_id desc) as seq
      from table
     ) t cross apply (
            select sum(t1.poin) as poin, sum(t1.freq) as freq
            from table t1
            where t1.member_id = t.member_id
     ) tt
where t.seq = 1;