按日期分组的SQL查询

Question

以下数据格式的SQL表

Datetime           Type    Id  
6/18/2018 8:00:00   A      1  
6/18/2018 9:00:00   A      2  
6/18/2018 10:00:00  A      3  
6/18/2018 11:00:00  B      4
6/18/2018 12:30:00  B      5  
6/18/2018 13:15:00  A      6  
6/18/2018 14:00:00  A      7  

需要结果表

Type Startdate          Enddate            Count Changeovertime

A    6/18/2018 8:00:00  6/18/2018 10:00:00   3   NA  
B    6/18/2018 11:00:00  6/18/2018 12:30:00  2   1:00:00       
A    6/18/2018 13:15:00  6/18/2018 14:00:00  2   0:45:00  

你能帮我查询一下结果吗？

我正在使用sql server 2008 express edition。

此致 Dilipan。

Answer 1

您可以使用row_number()的差异：

select Type, min(datetime) as startdate, max(datetime) as enddate, count(*) as count
from (select *, row_number() over (partition by type order by id) seq
      from table
     ) t
group by Type, (Id-Seq);