Question

我有两张桌子。表1和表2

TABLE1                TABLE2
ID | SIZE | VALUE     ID  | SIZE | SCORE 
1  | LOW  | 1.0       1   | MID  | 3232
2  | MID  | 3.0       2   | MID  | 2321
3  | HIGH | 5.0       3   | HIGH | 3232

我想要的是更新TABLE2.SCORE，因此值将是TABLE1.value列，连接将是SIZE。

   OUTPUT:
      ID  | SIZE | SCORE 
      1   | MID  | 3.0
      2   | MID  | 3.0
      3   | HIGH | 5.0

我试过了： Update Table2 set SCORE=(select top(1) VALUE from TABLE1 join TABLE2 on table1.size=table2.size )但是这不起作用我得到了这个结果：

 OUTPUT:
  ID  | SIZE | SCORE 
  1   | MID  | 3.0
  2   | MID  | 3.0
  3   | HIGH | 3.0 <---- wrong

Answer 1

update a
set a.score=b.score
from table2 a join table1 b on a.id=b.id

Answer 2

您可以在JOIN中使用UPDATE：

update t2
    set t2.score = t1.score
    from table2 t2 join
         table1 t1
         on t2.size = t1.size;

您还可以使用相关子查询来跟踪您的模式：

update table2
    set t2.score = (select t1.score from table1 t1 where t1.size = table2.size);

子查询中不需要另一个JOIN。

Answer 3

试试这个

DECLARE @TABLE1  AS TABLE(ID INT , SIZE VARCHAR(10) , VALUE decimal(2,1))   
INSERT INTO @TABLE1
SELECT 1  , 'LOW'  , 1.0  UNION ALL    
SELECT 2  , 'MID'  , 3.0  UNION ALL    
SELECT 3  , 'HIGH' , 5.0      

DECLARE @TABLE2  AS TABLE(ID INT , SIZE VARCHAR(10) , SCORE INT)
INSERT INTO @TABLE2
SELECT 1   , 'MID'  , 3232 UNION ALL
SELECT 2   , 'MID'  , 2321 UNION ALL
SELECT 3   , 'HIGH' , 3232 


SELECT * FROM @TABLE2

UPDATE t2
SET SCORE=t1.VALUE
FROM @TABLE2 t2 inner join @TABLE1 t1 On t1.SIZE=t2.SIZE


SELECT ID,SIZE, CAST(SCORE AS DECIMAL(2,1)) AS SCORE

FROM @TABLE2

演示结果：http://rextester.com/VFF59681

Answer 4

您无需在JOIN中执行subquery，您可以直接将其表达为：

update table2 
       set score = (select top (1) t1.score from table1 t1 where t1.size = table2.size);

Answer 5

你可以这样做：

update table2
set table2.SCORE = table1.VALUE
from table2
join table1
on table2.SIZE = table1.SIZE

但是，为避免出现问题，您需要确保table1.SIZE为unique。

联合表中的MSsql更新列

5 个答案: