Question

我有一张桌子：

RuleID |  Code    |    Value
654     Branch          54
654     MessageType     MT103
654     Currency        USD
654     SourceSys       xyz
<!--Comment-Another set of RuleID data-->
656     Branch          54
656     MessageType     MT102
656     Currency        INR
--------So ON -------------
<!--Comment-Another set of RuleID data-->
658     Branch          54
658     MessageType     MT103
658     Currency        INR

每个RuleID最多都有5到6个代码和它们的值。它也可能有1个也是2个。例如，我为规则ID 654和其他656提供了2个设定值。

现在需要一个查询，我可以获得所有RuleID，其中Branch = 54，MessageType = MT102

我在下面尝试过： - （但这显然不起作用）

select RuleID 
from MyTable 
where (CODE='Branch' and Value='54') 
 and  (CODE='MessageType' and Value='MT102')

阅读联盟，但这也不适用。

认为加入应该在这里，但不能得到结果。

预期结果：我想查询Branch为54且MessageType为MT103的所有RuleID。所以预期结果是Ruleid-654,658

Answer 1

使用OR。

SELECT RuleID 
FROM MyTable 
WHERE (CODE = 'Branch' AND Value = '54') 
OR (CODE = 'MessageType' AND Value = 'MT102')

Answer 2

也许是这样的事情？

SQL> WITH test (ruleid, code, VALUE)
  2       AS (SELECT 654, 'Branch', '54' FROM DUAL
  3           UNION
  4           SELECT 654, 'MessageType', 'MT103' FROM DUAL
  5           UNION
  6           SELECT 654, 'Currency', 'USD' FROM DUAL
  7           UNION
  8           SELECT 654, 'SourceSys', 'xyz' FROM DUAL
  9           UNION
 10           --
 11           SELECT 656, 'Branch', '54' FROM DUAL
 12           UNION
 13           SELECT 656, 'MessageType', 'MT102' FROM DUAL
 14           UNION
 15           SELECT 656, 'Currency', 'INR' FROM DUAL)
 16    SELECT ruleid
 17      FROM test
 18     WHERE (   (    code = 'Branch'
 19                AND VALUE = '54')
 20            OR (    code = 'MessageType'
 21                AND VALUE = 'MT102'))
 22  GROUP BY ruleid
 23    HAVING COUNT (*) = 2;

    RULEID
----------
       656

SQL>

Answer 3

您可以使用交叉点

WITH MyTable as 
(
  SELECT 654 RuleId, 'Branch' code, '54' value FROM DUAL
  UNION
  SELECT 654, 'MessageType', 'MT103' FROM DUAL
  UNION
  SELECT 654, 'Currency', 'USD' FROM DUAL
  UNION
  SELECT 654, 'SourceSys', 'xyz' FROM DUAL
  UNION
  SELECT 656, 'Branch', '54' FROM DUAL
  UNION
  SELECT 656, 'MessageType', 'MT102' FROM DUAL
  UNION
  SELECT 656, 'Currency', 'INR' FROM DUAL
)
select RuleID 
from   MyTable 
where  CODE='Branch' 
and    Value='54'
intersect
select RuleID 
from   MyTable 
where  CODE='MessageType' 
and    Value='MT102'

查询从同一个表中的两个列上检查条件得到结果

3 个答案: