Question

所以我制作了一个计算和打印得分的数量，打击的碗，投球手和击球手在板球比赛中罢工的程序，但是当我完成我的代码时：

name = input('enter the name of the bowler\n=')  # we ask for the input
    bat_strike = input('enter the name of the batter on strike\n=')
    bat_non_strike = input('enter the name of the batter on the non strike\n=')
    bowls = 6  # this is the max number of bowls in a over
    bowls_bowled = 0
    runs_list = []
    bowls_list = []
    batter_list = []
    batter_list.append(bat_strike)
    for j in range(0, bowls):
        bowl_type = int(input('enter the number corresponding to the option regarding the bowl bowled right now\n1)wide bowl\n2)simple bowl\n3)no ball\n4)dead bowl\n5)1D\n= '))
        if bowl_type == 1:
            bowls_list.append('wd')
            runs_list.append(1)
            batter_list.append(bat_strike)
            bowls += 1
        elif bowl_type == 2:
            run = int(input('enter the number of runs scored on that bowl 1 for 1 run 2 for 2 runs 3 for 3 runs 4 for 4 runs or 0 for a dot ball\n='))
            if run == 1 or run == 3:
                batter_on_strike = input('enter wether the batter on strike is on non strike? y or n\n=')
                if batter_on_strike == 'y':
                    c = bat_strike
                    bat_non_strike = bat_strike
                    bat_non_strike = c
                    batter_list.append(bat_strike)
            runs_list.append(run)
            bowls_list.append(1)
            bowls_bowled += 1
        elif bowl_type == 3:
            bowls_list.append('no ball')
            runs_list.append(1)
            bowls += 1
            batter_list.append(bat_strike)
        elif bowl_type == 4:
            bowls_list.append('dead bowl')
            bowls += 1
            batter_list.append(bat_strike)
        elif bowl_type == 5:
            bowls_list.append('1D')
            bowls += 1
            runs_list.append(1)
            bowls_bowled += 1
            batter_list.append(bat_strike)

    for i in range(0, bowls-1):
        print(f'bowler={name} batter on strike={batter_list[i]} bowl bowled={bowls_list[i]} runs scored={runs_list[i]}')

它会产生以下错误

print（f'bowler = {name} batter on strike = {batter_list [i]} bow bowled = {bowls_list [i]} run scored = {runs_list [i]}'） IndexError：列表索引超出范围

我想用每个碗的for循环显示结果，但我一直收到这个错误任何人都有任何想法如何解决问题或更好的代码？

Answer 1

如果bowl_type为5，或者它是2，并且击球或非击球击球的击球手不是y，则不要追加任何内容batter_list。因此，如果发生这种情况，batter_list将不会与您的其他列表一样长。

如果所有6个碗都是5型，那么batter_list将为空，因此当然batter_list[4]会出错。

在这种情况下，您不清楚想要会发生什么，所以你应该如何修复它并不明显。

在这种情况下，一种可能性是batter_list.append(None)。或者也许是batter_list.append("n/a")，或者......您希望稍后在print中显示的内容。

另一种可能性是用一个dicts列表替换所有这些单独的列表：

bowl_info_list = []
for j in range(0, bowls):
    # ...
    if bowl_type == 1:
        bowl_info_list.append({'bowl': 'wd', 'runs': 1, 'batter': bat_strike})
# ...

for bowl_info in bowl_info_list:
    print(f'bowler={name} batter on strike={bowl_info["batter"]} bowl bowled={bowl_info["bowl"]} runs scored={bowl_info["runs"]}')

或者，甚至可能更好，使用class（可能是namedtuple或@dataclass）而非dict。

错误：列表索引超出for循环范围

1 个答案: