如何在perl中迭代多级哈希

Question

my $app = "info";
my %records;
for($i = 0; $i<5; $i++)
{
 push@{$records{$app}{"id"}},$i;
 push@{$records{$app}{"score"}}, $i+4;
}

所以有5个ID [0,1,2,3,4,5]和5个分数。我的问题是如何迭代每个id和相应的分数...请帮助我..基本上我想要打印这样的结果

id score
0   4
1   5
2   6
3   7
4   8 
5   9

Answer 1

试试这个：

print "id\tscore";
for($i=0; $i<5; $i++) {
    print "\n$records{$app}{id}[$i]\t$records{$app}{score}[$i]";
}

Answer 2

printf "id\tscore\n";
for my $app (keys %records) {
    my $apprecordref = $records{$app};
    my %apprecord = %$apprecordref;

    my $idlen = scalar(@{$apprecord{"id"}});
    for ($i = 0; $i < $idlen; $i++) {
        printf "%d\t%d\n", $apprecord{"id"}[$i], $apprecord{"score"}[$i];
    }
}

---

id  score
0    4
1    5
2    6
3    7
4    8

---

或者这是一种不同的方式，我认为这样做更容易：

my $app = "info";
my %records;
for (my $i = 0; $i < 5; $i++)
{
    # $records{$app} is a list of hashes, e.g.
    # $records{info}[0]{id}
    push @{$records{$app}}, {id=>$i, score=>$i+4};
}

printf "id\tscore\n";
for my $app (keys %records) {
    my @apprecords = @{$records{$app}};

    for my $apprecordref (@apprecords) {
        my %apprecord = %$apprecordref;
        printf "%d\t%d\n", $apprecord{"id"}, $apprecord{"score"};
    }
}