函数回调循环2次

Question

def callback(channel):
    print("WARNING! FLAME DETECTED!!!\n")
    pygame.mixer.music.play()
    firebase.post("/Report/Location", alamat)
    firebase.post("/Report/Time", masa)
    lcd_string("  FIRE DETECTED  ",LCD_LINE_1)
    lcd_string(masa,LCD_LINE_2)
    print ("SUCCESSFULL REPORTED\n" +"Time : " + masa + "\nLocation : " + alamat)   


GPIO.add_event_detect(channel, GPIO.FALLING, bouncetime=300)  # let us know when the pin goes HIGH or LOW

GPIO.add_event_callback(channel, callback)  # assign function to GPIO PIN, Run function on change



# infinite loop

while True:

    time.sleep(10)
    lcd_init()

您好，有人可以解释一下为什么上面这段代码循环功能2次。当我删除

时，这让我更加困惑

firebase.post("/Report/Location", alamat)
firebase.post("/Report/Time", masa)

代码不会循环该函数。

Answer 1

当解释器读取exit（）语句时，据我所知，它突破了无限循环，程序执行终止。