Question

我试图在javascript / jquery中组合2个对象数组，用相同的键（代码）匹配它们。这些对象数组存储在2个独立的json文件中。

我已将这些文件删除了

如果有人可以提供帮助，请提前致谢。

对象1：

[{
    "code": "abc",
    "participant": {
        "firstname" : "Joe",
        "lastname" : "Blogs"
    }
},
{
    "code": "def",
    "participant": {
        "firstname" : "Anna",
        "lastname" : "Smith"
    }
}]

对象2：

[{
    "city": "london",
    "selfemployed": {
        "job" :"Builder",
        "code": "abc",
        "participant": {
            "firstname" : "Joe",
            "lastname" : "Blogs"
        }
    },
    "company" : {
        "job": "Shopkeeper",
        "code": "def",
        "participant": {
            "firstname" : "Anna",
            "lastname" : "Smith"
        }
    }
}]

需要的结果：

var file1 = 'url/file1.json';
var file1 = 'url/file2.json';

const joinJson = (file1, file2) => {
    $.getJSON(file, function(data1) {
        return data1;

    });

    $.getJSON(file2, function(data2) {
        return data2;

    });

    // do stuff with data1 and data2
}
console.log(joinJson());

我的一个问题是我无法从.json文件中返回该对象

import requests
from bs4 import BeautifulSoup

url = "https://www.reuters.com/finance/stocks/company-officers/MPAPss.BO"

response = requests.get(url)
soup = BeautifulSoup(response.content, 'html.parser')
table = soup.find('table', {'class': 'dataTable'})
for row in table.find_all("tr")[1::1]:
    col = row.find_all("td")
    name = col[0].get_text(strip=True)
    year = col[2].get_text(strip=True)
    position = col[3].get_text(strip=True)
    print("Name: {} Year: {} Position: {}".format(name,year,position))

Answer 1

您可以选择Map并为结果构建新对象，方法是为新对象选择所需的代码信息。

此提案使用带有babel的对象的rest属性为旧用户代理。

＆＃13;

var cities = [{ city: "london", selfemployed: { job: "Builder", code: "abc" }, company: { job: "Shopkeeper", code: "def" } }],
    codes = [{ code: "abc", participant: { firstname: "Joe", lastname: "Blogs" } }, { code: "def", participant: { firstname: "Anna", lastname: "Smith" } }],
    codesMap = new Map(codes.map(({ code, participant }) => [code, participant])),
    result = cities.map(
        ({ city, ...items }) =>
            Object.assign({ city }, ...Object.entries(items).map(
                ([k, v]) => ({ [k]: Object.assign({}, v, codesMap.get(v.code)) })
            ))
    );

console.log(result);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

Answer 2

问题是你正在异步获取文件，并在异步操作的回调中返回数据，这无处可去。这样的事情会更好：

var file1 = 'url/file1.json';
var file1 = 'url/file2.json';

const joinJson = (file1, file2) => {
    $.getJSON(file, function(data1) {
        // async operation 1 complete. Start operation 2.
        $.getJSON(file2, function(data2) {
            // async operation 2 complete
            // data1 and data2 are now available here
            console.log("Data 1:", data1);
            console.log("Data 2:", data2);

            // This will merge the keys of both objects
            // but you can replace it with custom merging logic
            var merged = Object.assign(data1, data2);
            console.log(merged);
        });
    });   
}

这里的问题是你不能做console.log(joinJson());之类的事情。您可能需要类似Promise的内容。

按键合并json文件中的2个对象数组

2 个答案: