Question

文件内容为：

1
name
linux
unix
---
he is
going to
learn
4
this is my
second difference
---
how to store
each difference in a variable

对于（number（1）和pattern“---”）之间的每个内容，我需要将值存储在数组中：之前和之后

例如：在[0]

之前回显$

name
linux
unix

在[0]

之后回显$

he is
going to
learn

现在我们看到数字：4 现在我们需要移动数组的索引并将内容存储在其中。在[1]

之前回显$

this is my
second difference

在[1]

之后回显$

how to store
each difference in a variable

我是shell的新手。你能帮帮我吗？提前谢谢。

这是片段。

i=0;
while read line;
do
if grep '[0-9].*' == $line // checks if it starts with a digit
then
$line=$line+1 ( from the next line before " ---" store it in base )
while "$line" != "---"
$line=$line+1
do
base[$i]=$line 
i=$(( i+1 ));
echo $base[$i]
done
fi
done <rit.log
echo "$base"

Answer 1

#!/usr/bin/env bash

before=() after=()
del=$'\n' is_after=1 i=-1

while IFS= read -r line; do
    [[ $line =~ ^[0-9]$ ]] && ((i++))
    [[ $line =~ ^([0-9]+|---)$ ]] && { ((is_after=!is_after)); continue; }

    if ((is_after)); then
        after[i]+=$line$del
    else
        before[i]+=$line$del
    fi
done < data

# trim the last delimiter
after=("${after[@]%?}")
before=("${before[@]%?}")

在匹配模式之前和之后将内容存储在数组中

1 个答案: