Question

我正在尝试找到选择具有最高特定属性值的对象（在这种情况下，错误答案的数量）并返回另一个属性（名称）的最佳方法。例如。以下对象应返回Mark：

[
{name: "Henry", age: "NYN", attempts: 3, wrong: 2},
{name: "Mark", age: "NNNY", attempts: 4, wrong: 3},
{name: "Beth", age: "", attempts: 0, wrong: 0},
{name: "Sally", age: "YYNY", attempts: 4, wrong: 1},
]

最好的解决方法是什么（在JavaScript中）？谢谢你的帮助！

Answer 1

这是一个简单的方法：

var objArray=[
{name: "Henry", age: "NYN", attempts: 3, wrong: 2},
{name: "Mark", age: "NNNY", attempts: 4, wrong: 3},
{name: "Beth", age: "", attempts: 0, wrong: 0},
{name: "Sally", age: "YYNY", attempts: 4, wrong: 1},
];
function getNameOfMostWrong(){
  //Set first object in array for most wrong as default
  var mostWrongPerson=objArray[0];
  for(var person in objArray){
    if(objArray[person].wrong > mostWrongPerson.wrong){
      mostWrongPerson=objArray[person];
    }
  }
  return mostWrongPerson.name;
}

Answer 2

您可以使用简单的for循环来检查最高wrong值并选择该对象。这将具有O(n)的复杂度，类似于线性搜索算法。

＆＃13;

var arr = [
{name: "Henry", age: "NYN", attempts: 3, wrong: 2},
{name: "Mark", age: "NNNY", attempts: 4, wrong: 3},
{name: "Beth", age: "", attempts: 0, wrong: 0},
{name: "Sally", age: "YYNY", attempts: 4, wrong: 1},
];

var highest = arr[0].wrong, index;
for(var i=1; i<arr.length; i++){
  if(arr[i].wrong > highest){
     highest = arr[i];
     index = i;
  }
}
var highestWrong = arr[index];
console.log('highest wrong attempt is done by', highestWrong.name);

＆＃13;

在多维数组中选择具有最高值的对象

2 个答案: