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Question

我已经尝试过将列表转换为其他问题中的字符串，但输出似乎不是我应该得到的。我有[['This','is','here.'],['Second','sentence','here.']]的输入，我想将其转换为字符串并保存到带有输出的文本文件中：

This is here.
Second sentence here.

我做的是，

list = [['This','is','here.'],['Second','sentence','here.']]
with open(outfile, 'w') as newfile:
    newfile.write(str('\n'.join((str(i) for i in list))))

.txt文件中的输出是：

['This', 'is', 'here.']
['Second', 'sentence', 'here.']

非常感谢帮助。谢谢！

Answer 1

您可以尝试lst = '\n'.join(' '.join(i) for i in txt)（此外，这很好使用 list以外的变量名称：

txt = [['This','is','here.'],['Second','sentence','here.']]
with open(outfile, 'w') as newfile:
    lst = '\n'.join(' '.join(i) for i in txt)
    newfile.write(lst)

更新

看起来列表中的项目有None，您可以按照other answer中的说明对其进行过滤，并使用以下内容：

txt = [['This','is','here.'],['Second','sentence','here.'], ['Here',None, 'is']]
lst = '\n'.join(' '.join(list(filter(None.__ne__, i))) for i in txt)
print(lst)

结果：

This is here.
Second sentence here.
Here is

正如下面的评论中所建议的那样，在这种情况下，只需添加其他时间结果即可将filter与list comprehension进行比较，list comprehension更快：

%%timeit
txt = [['This','is','here.'],['Second','sentence','here.'], ['Here',None, 'is']]
lst = '\n'.join(' '.join(list(filter(None.__ne__, i))) for i in txt)

# Result: 100000 loops, best of 3: 4.52 µs per loop

%%timeit
txt = [['This','is','here.'],['Second','sentence','here.'], ['Here',None, 'is']]
lst = '\n'.join(' '.join(([j for j in i if j != None])) for i in txt)

# Result: 100000 loops, best of 3: 3.28 µs per loop

Answer 2

您可以使用str.join将列表转换为字符串

>>> l=[['This','is','here.'],['Second','sentence','here.']]
>>> print ('\n'.join([' '.join(e) for e in l]))
This is here.
Second sentence here.
>>>

如何将单词列表列表转换为字符串作为句子？

2 个答案:

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