Question

我已经让selenium完美地工作但我想知道如何点击我输入的字符串的链接：

from selenium import webdriver  
from selenium.common.exceptions import NoSuchElementException  
from selenium.webdriver.common.keys import Keys  

url = "http://www.howlongtobeat.com"
driver = webdriver.Chrome()
driver.get(url)

search_element = driver.find_element_by_name("global_search_box")
search_element.clear()
search_element.send_keys("God of War (2018)")
search_element.send_keys(Keys.RETURN)

link = driver.find_element_by_xpath("//div id=[@class='nav_playthroughs_load]")
link.click()

如何点击标题为“战神（2018）”的链接

我收到了这个错误：

WebDriverException                        Traceback (most recent call last)
<ipython-input-7-0343b11486bd> in <module>()
----> 1 search_element = driver.find_element_by_name("global_search_box")
      2 search_element.clear()
      3 search_element.send_keys("God of War (2018)")
      4 search_element.send_keys(Keys.RETURN)
      5 

~/anaconda3/lib/python3.6/site-packages/selenium/webdriver/remote/webdriver.py in find_element_by_name(self, name)
    485             element = driver.find_element_by_name('foo')
    486         """
--> 487         return self.find_element(by=By.NAME, value=name)
    488 
    489     def find_elements_by_name(self, name):

~/anaconda3/lib/python3.6/site-packages/selenium/webdriver/remote/webdriver.py in find_element(self, by, value)
    953         return self.execute(Command.FIND_ELEMENT, {
    954             'using': by,
--> 955             'value': value})['value']
    956 
    957     def find_elements(self, by=By.ID, value=None):

~/anaconda3/lib/python3.6/site-packages/selenium/webdriver/remote/webdriver.py in execute(self, driver_command, params)
    310         response = self.command_executor.execute(driver_command, params)
    311         if response:
--> 312             self.error_handler.check_response(response)
    313             response['value'] = self._unwrap_value(
    314                 response.get('value', None))

~/anaconda3/lib/python3.6/site-packages/selenium/webdriver/remote/errorhandler.py in check_response(self, response)
    240                 alert_text = value['alert'].get('text')
    241             raise exception_class(message, screen, stacktrace, alert_text)
--> 242         raise exception_class(message, screen, stacktrace)
    243 
    244     def _value_or_default(self, obj, key, default):

WebDriverException: Message: chrome not reachable
  (Session info: chrome=67.0.3396.79)
  (Driver info: chromedriver=2.35.528139 (47ead77cb35ad2a9a83248b292151462a66cd881),platform=Linux 4.15.0-23-generic x86_64)

感谢，

Answer 1

要点击带有战争之神（2018）的文字的链接，您必须诱导 WebDriverWait 以使元素可点击并且您可以使用以下任一解决方案：

LINK-TEXT ：

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.LINK_TEXT, "God of War (2018)"))).click()

CSS-SELECTOR ：

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "a.text_blue[title^='God of War']"))).click()

XPATH ：

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//a[@class='text_blue'][@title=\"God of War (2018)\"]"))).click()

用Selenium进行网页抓取 - 用javascript点击链接（无法找到元素）

1 个答案: