Question

假设发出了一个Web请求，它返回了一种类型的项目列表。我有一个Angular组件，用于呈现指定类型的数据。现在，如何将组件实例初始化为从Web请求获取的每个项目并以表格格式呈现它？

我没有自己做，也没有在网上获得任何有用的信息。能否请你帮忙？提前谢谢！

  @ViewChild('container', {read: ViewContainerRef}) container;

  constructor(public resolver: ComponentFactoryResolver) {
  }

  clicked(event) {
    const addressFactory = this.resolver.resolveComponentFactory(AddressComponent);
    const addressRef = this.container.createComponent(addressFactory);
    addressRef.instance.title = 'Home';
   }

我能做到这一点。但'容器'参考将变为硬编码。我想为返回的每个项动态创建一个add，并在其中插入填充的AddressComponent。我不能硬编码参考，因为我的动态。

Answer 1

没关系！我在谷歌搜索后找到了答案！

https://medium.com/@caroso1222/angular-pro-tip-how-to-dynamically-create-components-in-body-ba200cc289e6

import {
    Injectable,
    Injector,
    ComponentFactoryResolver,
    EmbeddedViewRef,
    ApplicationRef
} from '@angular/core';

@Injectable()
export class DomService {

  constructor(
      private componentFactoryResolver: ComponentFactoryResolver,
      private appRef: ApplicationRef,
      private injector: Injector
  ) { }

  appendComponentToBody(component: any) {
    // 1. Create a component reference from the component 
    const componentRef = this.componentFactoryResolver
      .resolveComponentFactory(component)
      .create(this.injector);

    // 2. Attach component to the appRef so that it's inside the ng component tree
    this.appRef.attachView(componentRef.hostView);

    // 3. Get DOM element from component
    const domElem = (componentRef.hostView as EmbeddedViewRef<any>)
      .rootNodes[0] as HTMLElement;

    // 4. Append DOM element to the body
    document.body.appendChild(domElem);

    // 5. Wait some time and remove it from the component tree and from the DOM
    setTimeout(() => {
        this.appRef.detachView(componentRef.hostView);
        componentRef.destroy();
    }, 3000);
  }
}

如何动态渲染表格布局中的角度组件？

1 个答案: