Question

我正在寻找答案，但我没有找到与我的问题类似的东西。

我有简单的REST API，写作学习项目，我很难在控制器中创建正确的POST方法。其他基本命令工作正常，只是这一点使事情变得艰难。

我的代码：

控制器：

@CrossOrigin(origins = "*")
@RestController
@RequestMapping("/v1/foo")
public class TaskController {

    private final DbService dbService;
    private final FooMapper fooMapper;

    @Autowired
    public FooController(DbService dbService, FooMapper fooMapper) {
        this.dbService = dbService;
        this.fooMapper = fooMapper;
    }

    @RequestMapping(method = RequestMethod.POST, value = "/createFoo", consumes = APPLICATION_JSON_VALUE)
    public void createFoo(@RequestBody FooDto fooDto) {
         dbService.saveFoo(fooMapper.mapToFoo(FooDto));
    }

存储库：

public interface FooRepository extends CrudRepository<Foo, Long> {

    @Override
    List<Foo> findAll();

    Optional<Foo> findByIdEquals(long fooId);

    @Override
    Foo save(Foo foo);

    @Override
    long count();

 }

服务：

@Service
public class DbService {

    @Autowired
    private FooRepository repository;

    public List<Foo> getAllFoos() {
        return repository.findAll();
    }

    public Foo saveFoo(final Foo foo) {
        return repository.save(foo);
    }

    public Optional<Foo> getFoo(final long fooId) {
        return repository.findByIdEquals(fooId);
    }

    public void deleteFoo (final long FooId) {
        repository.deleteById(fooId);
    }
}

使用以下代码测试上述代码：

@Test
    public void testShouldCreateTask() throws Exception {
        //Given
        FooDtofookDto = new FooDto(1L, "Title", "Content");
        Foo foo = new Foo(1L, "Title after", "Content after");

        when(dbService.saveFoo(foo)).thenReturn(foo);

        //When&&Then
        Gson gson = new Gson();
        String jsonContent = gson.toJson(fooDto);
        System.out.println(jsonContent);
        mockMvc.perform(post("/v1/foo/createFoo")
                .contentType(MediaType.APPLICATION_JSON)
                .characterEncoding("UTF-8")
                .content(jsonContent))
                .andExpect(status().isOk())
                .andExpect((jsonPath("$.title", is("Title after"))));
    }

给出了这个结果：

MockHttpServletRequest:
      HTTP Method = POST
      Request URI = /v1/foo/createFoo
       Parameters = {}
          Headers = {Content-Type=[application/json;charset=UTF-8]}
             Body = {"id":1,"title":"Title","content":"Content"}
    Session Attrs = {}

Handler:
             Type = com.crud.foos.controller.FooController
           Method = public void    com.crud.foos.controller.FooController.createFoo(java.lang.String,com.crud.foos.domain.FooDto)

Async:
    Async started = false
     Async result = null

Resolved Exception:
             Type = null

ModelAndView:
        View name = null
             View = null
            Model = null

FlashMap:
       Attributes = null

MockHttpServletResponse:
           Status = 200
    Error message = null
          Headers = {}
     Content type = null
             Body = 
    Forwarded URL = null
   Redirected URL = null
          Cookies = []

java.lang.AssertionError: No value at JSON path "$.title"

如果我理解正确处理了POST请求，但由于某种原因，序列化的对象体丢失了，因此我收到了＃34;没有值＆＃34;结果，但状态是200.我正在咨询大量的页面和来源，我无法在提供的代码中找到错误。如果有任何额外信息有帮助，我当然会提供。

POST方法将反序列化的json作为空字符串传递

0 个答案: