CRUD json与java servlet

Question

我有一个Dog类，它有名字，年龄和身高。我想用这些值创建一个JSON对象。然后，我想创建方法CreateJsonServlet，ModifyJsonServlet和DeleteJsonServlet。我需要生成一个JSON对象，然后传递它来创建，更新和删除JSON方法。

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class CreateServlet extends HttpServlet {

@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
    super.doPost(req, resp);

    Dog dog = new Dog();

    dog.setName(req.getParameter("name"));
    dog.setHeight(Integer.parseInt(req.getParameter("height")));
    dog.setAge(Integer.parseInt(req.getParameter("age")));


    String name = dog.getName();
    int age = dog.getAge();
    int height = dog.getHeight();



    resp.getWriter().write(dog.toString());
    resp.getWriter().flush();
    resp.getWriter().close();

}

}

这是狗类：

package com.Google;

public class Dog {

private String name;
private int age;
private int height;

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public int getAge() {
    return age;
}

public void setAge(int age) {
    this.age = age;
}

public int getHeight() {
    return height;
}

public void setHeight(int height) {
    this.height = height;
}

@Override
public String toString() {
    return "Dog{" +
            "name='" + name + '\'' +
            ", age=" + age +
            ", height=" + height +
            '}';
}

}