Question

我正在使用curl获取网页并将其存储在python中的变量中。

var = '<body><img src=\"https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg\" style=\"display: none;\"/><div class=\"wrapper\">'

我只想要字符串中的链接，例如：

"https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg"

我通过将正则表达式的开头定义为“（https | http）并结束为”来尝试与正则表达式匹配：

x = re.findall(r'"(https|http)*"$', var)
print(x)

但我没有得到输出。请提前帮助我。

>>>[]

Answer 1

使用re.search

import re
var = '<body><img src=\"https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg\" style=\"display: none;\"/><div class=\"wrapper\">'
m = re.search("src=\"(?P<url>.*?)\"", var)
if m:
    print m.group('url')

<强>输出：

https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg

Answer 2

@Manoj ，您还可以使用src方法多次检索split()属性的值，如下所示。

»使用lambda函数（1行语句）

var = '<body><img src=\"https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg\" style=\"display: none;\"/><div class=\"wrapper\">'

get_url = lambda html: html.split('=')[1].split('\"')[1]
print(get_url(var))

»输出

https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg

让我们在多个陈述中扩展上述方法，以了解实际的直接过程。

var = '<body><img src=\"https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg\" style=\"display: none;\"/><div class=\"wrapper\">'
print(var, "\n")
# <body><img src="https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg" style="display: none;"/><div class="wrapper">

parts1 = var.split("=")
print(parts1, "\n")
# ['<body><img src', '"https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg" style', '"display: none;"/><div class', '"wrapper">']

parts2 = parts1[1].split('\"')
print(parts2, "\n")
# ['', 'https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg', ' style']

print(parts2[1])
# https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg

»输出

E:\Users\Rishikesh\Python3\Practice\Temp>python GetUrls.py
<body><img src="https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg" style="display: none;"/><div class="wrapper">

['<body><img src', '"https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg" style', '"display: none;"/><div class', '"wrapper">']

['', 'https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg', ' style']



https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg

Answer 3

使用beautifulsoup，您可以搜索a或img并检查属性：

例如：

from bs4 import BeautifulSoup as soup

var = '<body><a href=\"https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg\"><img src=\"https://cdn.neow.in/news/images/uploaded/2018/06/Gaming sloop, preview group, hardware _mediump.jpg\" style=\"display: none;\"/></a><div class=\"wrapper\">'
page_soup = soup(var, "html.parser")

links = []

for elm in page_soup.findAll(['a', 'img']):
    if elm.has_attr('href'):
        links.append(elm.get('href'))
    if elm.has_attr('src'):
        links.append(elm.get('src'))

print(links)

Demo

如何从python中的字符串中获取url

3 个答案: