Question

我在jQuery中有以下关联数组：

var main_new_smarket_image_tags_list = {
    1: "value1",
    4: "value4",
    2: "value2",
    8: "value8"
};

我想根据索引的值删除元素。例如，删除索引为2的元素。然后它看起来像这样：

main_new_smarket_image_tags_list = {
    1: "value1",
    4: "value4",
    8: "value8"
};

Answer 1

我正在修改我的答案，因为我对你的问题和实际代码感到困惑。你的问题涉及数组，但你的代码是一个对象。

由于您正在使用对象，因此需要获取要删除的值的键，然后调用delete object[key]。

实施例

＆＃13;

var main_new_smarket_image_tags_list = {
   1: "value1",
   4: "value4",
   2: "value2",
   8: "value8"
};

var key = 2;

delete main_new_smarket_image_tags_list[key];
//{"1": "value1", "4": "value4", "8": "value8"}
console.log(main_new_smarket_image_tags_list);

＆＃13;

Answer 2

以下是解决方案：https://codepen.io/creativedev/pen/eKGXVr

var main_new_smarket_image_tags_list = {
    1: "value1",
    4: "value4",
    2: "value2",
    8: "value8"
};
var removeindex = 2;
var newcontent = {};
$.each(main_new_smarket_image_tags_list, function(i,v){
  if(i != removeindex){
    newcontent[i] = v; 
  }
})
console.log(newcontent);

Answer 3

你能试试吗？

ArrayName.splice（indexValueOfArray，1）;

另请点击下方。

Remove Array Value By index in jquery

Answer 4

您可以遍历整个对象并delete值匹配的键：

var main_new_smarket_image_tags_list = {
    1: "value1",
    4: "value4",
    2: "value2",
    8: "value8"
};

var value_to_delete = "value2"; // <-- could come from anywhere.

for (var key in main_new_smarket_image_tags_list) {  // <-- loops over all items
    if (main_new_smarket_image_tags_list[key] === value_to_delete) { // <- checks for the value
        delete main_new_smarket_image_tags_list[key];  // <-- this deletes they key (along with the value)
    }
}

通过索引的值从关联数组中删除元素

4 个答案: