Question

我有一个带有ListView控制器的wpf窗口和一堆项目。

<ListView Name="lvUsers" SelectionChanged="lvUsers_SelectionChanged">
    <ListView.View>
        <GridView>
            <GridViewColumn Header="Name" Width="120" DisplayMemberBinding="{Binding Name}" />
            <GridViewColumn Header="Age" Width="50" DisplayMemberBinding="{Binding Age}" />
            <GridViewColumn Header="Mail" Width="150" DisplayMemberBinding="{Binding Mail}" />
        </GridView>
    </ListView.View>
</ListView>

我可以将此ListView转换为List<T>，以便我可以在XML文件中对其进行序列化吗？

我试过了：

foreach (ListViewItem item in lvUsers.SelectedItems)
{
    foreach (ListViewItem.ListViewSubItem subItem in lvUsers.SubItems)
    {
    }
}

但是这段代码不起作用，因为ListViw不会包含SubItem属性。

Answer 1

要序列化您的数据，您的数据必须是可序列化的。你在哪里以及如何定义它？最好的方法是定义ObservableCollection<YourClass>并在ItemsSource中将其用作ListView。如果YourClass是可序列化的，则可以从该数据集合中获取数据并对其进行序列化。

<Window 
x:Class="WpfApp2.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:local="clr-namespace:WpfApp2"
mc:Ignorable="d"
Title="MainWindow" Height="450" Width="800">
<StackPanel>
    <Button Click="ButtonBase_OnClick">Serialize</Button>

    <ListView ItemsSource="{Binding AllMyData}">
        <ListView.View>
            <GridView>
                <GridViewColumn Header="Name" Width="120" DisplayMemberBinding="{Binding Name}" />
                <GridViewColumn Header="Age" Width="50" DisplayMemberBinding="{Binding Age}" />
                <GridViewColumn Header="Mail" Width="150" DisplayMemberBinding="{Binding Mail}" />
            </GridView>
        </ListView.View>
    </ListView>
</StackPanel>

using System.Collections.Generic;
using System.Collections.ObjectModel;
using System.Diagnostics;
using System.IO;
using System.Linq;
using System.Windows;
using System.Xml;
using System.Xml.Serialization;

namespace WpfApp2
{
    public partial class MainWindow : Window
    {
        public class YourClass
        {
            public string Name { get; set; }
            public string Age { get; set; }
            public string Mail { get; set; }
        }

        public ObservableCollection<YourClass> AllMyData { get; set; }

        public MainWindow()
        {
            InitializeComponent();
            AllMyData = new ObservableCollection<YourClass>();
            for (var i = 0; i < 3; i++)
            {
                AllMyData.Add(new YourClass { Name = i.ToString() });
            }
            this.DataContext = this;
        }

        private void ButtonBase_OnClick(object sender, RoutedEventArgs e)
        {
            XmlSerializer xsSubmit = new XmlSerializer(typeof(List<YourClass>));
            var subReq = AllMyData.ToList();
            var xml = "";

            using (var sww = new StringWriter())
            {
                using (XmlWriter writer = XmlWriter.Create(sww))
                {
                    xsSubmit.Serialize(writer, subReq);
                    xml = sww.ToString(); // Your XML
                    Debugger.Break();
                }
            }
        }
    }
}

ListView进入列表

1 个答案: