Question

我有这样的JSON，它存储在变量中。

data=[  
   [  
      {  
         "fdate":"01-01-2018",
         "pdate":"31-12-2018",
         "range":"01-01-2018 - 31-12-2018",
         "nlist":[  ],
         "nplist":[  ]
      }
   ],
   [  
      {  
         "fdate":"01-01-2018",
         "pdate":"31-12-2018",
         "range":"01-01-2018 - 31-12-2018",
         "nlist":[  ],
         "nplist":[  ]
      },
      {  
         "efdate":"21-01-2018",
         "expdate":"31-12-2018",
         "range":"21-01-2018 - 31-12-2018",
         "nlist":[  ],
         "nplist":[  ]
      }
   ]
]

如何从打印机文件中获取范围，请提供建议。

我试图像这样检索，但它无法正常工作

for(let i=0; i< this.data.length; i++){
            this.other +=  this.data[i].range;
            }
Console.log(this.other);

如果有更好的方法，请建议或告诉我

Answer 1

你可以这样做：

for(let i=0; i < this.data.length;i++){
    for(let j=0; j < this.data[i].length;j++){
        this.other +=  this.data[i][j].range;
        console.log(this.data[i][j].range); // What you want to do here...
    }   
}

以下是工作示例：https://stackblitz.com/edit/angular-8j5hkk

希望这能帮到你!!!!

Answer 2

＆＃13;

var data=[  
   [  
      {  
         "fdate":"01-01-2018",
         "pdate":"31-12-2018",
         "range":"01-01-2018 - 31-12-2018",
         "nlist":[  ],
         "nplist":[  ]
      }
   ],
   [  
      {  
         "fdate":"01-01-2018",
         "pdate":"31-12-2018",
         "range":"01-01-2018 - 31-12-2018",
         "nlist":[  ],
         "nplist":[  ]
      },
      {  
         "efdate":"21-01-2018",
         "expdate":"31-12-2018",
         "range":"21-01-2018 - 31-12-2018",
         "nlist":[  ],
         "nplist":[  ]
      }
   ]
]

var calc = calculateRange(data);
console.log(calc)
function calculateRange(_data){
   var r = "";
   for(var i=0;i<_data.length;i++){
       var isArray = Array.isArray(_data[i]);
       if(isArray){
        r+=calculateRange(_data[i]);
       }else{
        var x = _data[i].range;
        r+= typeof x != "undefined"? x:"";
       }
   }
   return r;
}

＆＃13;

您可以使用逻辑循环，示例在上面。

Answer 3

this.data=[
  [
     {
        "fdate":"01-01-2018",
        "pdate":"31-12-2018",
        "range":"01-01-2018 - 31-12-2018",
        "nlist":[  ],
        "nplist":[  ]
     }
  ],
  [
     {
        "fdate":"01-01-2018",
        "pdate":"31-12-2018",
        "range":"01-01-2018 - 31-12-2018",
        "nlist":[  ],
        "nplist":[  ]
     },
     {
        "efdate":"21-01-2018",
        "expdate":"31-12-2018",
        "range":"21-01-2018 - 31-12-2018",
        "nlist":[  ],
        "nplist":[  ]
     }
  ]
]
for(let i=0; i< this.data.length; i++){
for(let t = 0; t < this.data[i].length; t++) {
     console.log(this.data[i][t].range);
      }
    }

在html页面中，您可以像这样检索

 <div *ngFor="let i of data">
    <p *ngFor="let t of i">{{t.range}}</p>
</div>

或在你的ts中，你可以这样做

 for(let i=0; i< this.data.length; i++){
     for(let t = 0; t < this.data[i].length; t++) {
          console.log(this.data[i][t].range);
           }}

如何从对象角度数组5的数组中检索值

3 个答案: