我有以下方法,但不太优雅。如果可能的话,我想用ToDictionary来解决这个问题。感谢您提供任何帮助,因为我很新。
var excel = new ExcelQueryFactory(@"E:\MAHipotCepaStationProgram.xlsx");
//get list of program names
List<string> testNames = new List<string>();
testNames.AddRange(excel.Worksheet().ToList()
.Where(s => s["Program #"].Value.ToString() == "Program Title")
.Select(s => s[1].Value.ToString()));
//get list of program numbers
List<int> testNumbers = new List<int>();
testNumbers.AddRange(excel.Worksheet().ToList()
.Where(s => s["Program #"].Value.ToString() == "Program #")
.Select(s => Convert.ToInt32(s[1].Value)));
//combine them
Dictionary<int, string> programs = new Dictionary<int, string>();
for (int x = 0; x < testNames.Count-1; x++)
{
if (!programs.ContainsKey(Convert.ToInt32(testNumbers[x])))
{
programs.Add(Convert.ToInt32(testNumbers[x]), testNames[x]);
}
else
{
testNumbers[x].Dump("Duplicate Found");
}
}
programs.Dump("Dict");
这就像我得到的那样接近,但不对。错误:&#34;需要IEnumberable字符串类型的接收器,它不能与我一起计算:
var excel = new ExcelQueryFactory(@"E:\MAHipotCepaStationProgram.xlsx");
Dictionary<string, string> programsDict = excel.Worksheet().ToDictionary<string, string>(
e => e["Program #"].Value.ToString() == "Program Title")
.Select(s => s[1].Value.ToString()),
f => f.Where(d => d.Value.ToString() == "Program #").ToString());
答案 0 :(得分:0)
您可以使用sigle LINQ查询过滤值。这将返回excel中的名称和数字列:
var sampleExcel = new ExcelQueryFactory(@"I:\Book1.xlsx");
var sampleWorksheet = from workSheet in sampleExcel.Worksheet("Sheet1") select workSheet;
var selectedValues = from excelRow in sampleExcel.Worksheet()
select new { name = excelRow[0], number =Convert.ToInt32(excelRow[1]) };
foreach (var item in selectedValues)
{
Console.WriteLine(string.Format("Name is {0} ,number is {1}",item.name,item.number));
}
Dictionary<int, string> dict = new Dictionary<int, string>();
foreach (var item in selectedValues)
{
dict.Add(item.number, item.name);
Console.WriteLine(string.Format("Name is {0} ,number is {1}", item.name, item.number));
}
上述LINQ查询的等效lambda表达式:
var selectedValues1 = sampleExcel.Worksheet().Select(x => new { name = x[0], number = x[1] });
答案 1 :(得分:0)
快来看看:
do.call(rbind, lapply(2:4, function(x) {
do.call(rbind, combn(4, x, function(y) {
data.frame(comb. = paste(y, collapse = ""),
Var_comb = paste(c("", y), collapse = "x"),
index = sum(G[y,y] %*% B[y] * A[y]),
stringsAsFactors = FALSE)
}, simplify = FALSE))
}))
comb. Var_comb index
1 12 x1x2 7.438186
2 13 x1x3 83.270451
3 14 x1x4 37.435149
4 23 x2x3 68.331049
5 24 x2x4 21.273907
6 34 x3x4 145.311921
7 123 x1x2x3 87.071171
8 124 x1x2x4 39.689388
9 134 x1x3x4 174.958491
10 234 x2x3x4 150.810089
11 1234 x1x2x3x4 180.665871
你只需要NuGet&#34; System.Interactive&#34;获得Dictionary<int, string> programsDict =
excel
.Worksheet()
.Select(x => new { A = x[0].ToString(), B = x[1].ToString() })
.ToArray()
.Where(x => new [] { "Program #", "Program Title" }.Contains(x.A))
.Buffer(2)
.Select(x => new { title = x[0].B, number = int.Parse(x[1].B) })
.ToDictionary(x => x.number, x => x.title);
运营商。
或者使用此实现:
.Buffer(int)