目标:
加载.thumbnail
div中的图像后,红色边框应变为绿色
的jsfiddle: https://jsfiddle.net/3k8xy2cf/
var container;
var img;
$("#products .thumbnail").each(function() {
container = $(this);
img = new Image();
img.src = $(container).find('img').attr('src');
img.onload = function() {
$(container).addClass('loaded');
}
});
.product {
float: left;
border: 5px solid red;
}
.product.loaded {
border-color: green;
}
.product img {
width: 25%;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="products">
<div class="product">
<div class="thumbnail">
<img src="https://placehold.it/600x600" alt="">
</div>
</div>
<div class="product">
<div class="thumbnail">
<img src="https://placehold.it/800x800" alt="">
</div>
</div>
</div>
答案 0 :(得分:2)
您的代码比它需要的复杂得多。您不需要each()
循环,并且您当然不需要从已存在的元素中创建新的img
元素。
相反,您可以在load()
元素上使用img
事件处理程序,将类添加到父.thumbnail
,如下所示:
$('#products .thumbnail img').on('load', function() {
$(this).closest('.thumbnail').addClass('loaded');
});
.thumbnail {
border: 2px solid #C00;
}
.thumbnail.loaded {
border-color: #0C0;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="products">
<div class="product">
<div class="thumbnail">
<img src="https://placehold.it/125x125" alt="">
</div>
</div>
<div class="product">
<div class="thumbnail">
<img src="https://placehold.it/150x150" alt="">
</div>
</div>
</div>