Question

我有这样的架构：

"foo": {"type": "string", "format": "time"}

我试过new (new Date()).toISOString()它有这种格式：

"2018-06-12T08:59:01.135Z"

错误：

jsonschema.exceptions.ValidationError: '2018-06-12T08:59:01.135Z' is not a 'time'

Answer 1

{ "format": "time" }使用RFC-3339第5.6节“Internet日期/时间格式”。

http://json-schema.org/latest/json-schema-validation.html#rfc.section.7.3.1 https://tools.ietf.org/html/rfc3339#section-5.6

Answer 2

您可以转换日期"../../node_modules/@types"

{
"compilerOptions": {
    "module": "commonjs",
    "esModuleInterop": true,
    "target": "es6",
    "typeRoots": [
        "../../node_modules/@types"
    ],
    "noImplicitAny": true,
    "moduleResolution": "node",
    "sourceMap": true,
    "outDir": "server",
    "baseUrl": "."
  },
  "include": [
      "src/**/*"
  ]
}

MDN docs

如何为jsonschema生成时间字符串

2 个答案: