Scala脚本不能在Ubuntu上运行

时间:2018-06-15 13:13:13

标签: scala ubuntu scala-script

我有一个以前工作的Scala脚本,当我尝试在新PC上运行它时,编译失败。

所以我制作了简单的脚本进行测试:

#!/bin/sh
exec scala -J-Xmx2g "$0" "$@"
!#

println("test")

尝试运行它我得到了:

test.scala 
error: Compile server encountered fatal condition: java.nio.ByteBuffer.clear()Ljava/nio/ByteBuffer;
java.lang.NoSuchMethodError: java.nio.ByteBuffer.clear()Ljava/nio/ByteBuffer;
at scala.tools.nsc.io.SourceReader.read(SourceReader.scala:61)
at scala.tools.nsc.io.SourceReader.read(SourceReader.scala:40)
at scala.tools.nsc.io.SourceReader.read(SourceReader.scala:49)
at scala.tools.nsc.Global.getSourceFile(Global.scala:395)
at scala.tools.nsc.Global.getSourceFile(Global.scala:401)
at scala.tools.nsc.Global$Run$$anonfun$30.apply(Global.scala:1607)
at scala.tools.nsc.Global$Run$$anonfun$30.apply(Global.scala:1607)
at scala.collection.immutable.List.map(List.scala:284)
at scala.tools.nsc.Global$Run.compile(Global.scala:1607)
at scala.tools.nsc.StandardCompileServer.session(CompileServer.scala:151)
at scala.tools.util.SocketServer$$anonfun$doSession$1$$anonfun$apply$1.apply(SocketServer.scala:74)
at scala.tools.util.SocketServer$$anonfun$doSession$1$$anonfun$apply$1.apply(SocketServer.scala:74)
at scala.util.DynamicVariable.withValue(DynamicVariable.scala:58)
at scala.Console$.withOut(Console.scala:65)
at scala.tools.util.SocketServer$$anonfun$doSession$1.apply(SocketServer.scala:74)
at scala.tools.util.SocketServer$$anonfun$doSession$1.apply(SocketServer.scala:69)
at scala.tools.nsc.io.Socket.applyReaderAndWriter(Socket.scala:49)
at scala.tools.util.SocketServer.doSession(SocketServer.scala:69)
at scala.tools.util.SocketServer.loop$1(SocketServer.scala:85)
at scala.tools.util.SocketServer.run(SocketServer.scala:97)
at scala.tools.nsc.CompileServer$$anonfun$execute$2$$anonfun$apply$mcZ$sp$1.apply$mcZ$sp(CompileServer.scala:218)
at scala.tools.nsc.CompileServer$$anonfun$execute$2$$anonfun$apply$mcZ$sp$1.apply(CompileServer.scala:213)
at scala.tools.nsc.CompileServer$$anonfun$execute$2$$anonfun$apply$mcZ$sp$1.apply(CompileServer.scala:213)
at scala.util.DynamicVariable.withValue(DynamicVariable.scala:58)
at scala.Console$.withOut(Console.scala:53)
at scala.tools.nsc.CompileServer$$anonfun$execute$2.apply$mcZ$sp(CompileServer.scala:213)
at scala.tools.nsc.CompileServer$$anonfun$execute$2.apply(CompileServer.scala:213)
at scala.tools.nsc.CompileServer$$anonfun$execute$2.apply(CompileServer.scala:213)
at scala.util.DynamicVariable.withValue(DynamicVariable.scala:58)
at scala.Console$.withErr(Console.scala:80)
at scala.tools.nsc.CompileServer$.execute(CompileServer.scala:212)
at scala.tools.nsc.CompileServer$.main(CompileServer.scala:180)
at scala.tools.nsc.CompileServer.main(CompileServer.scala)

看起来Scala正在编写我脚本附近的内容,但我不太清楚如何调试它并修复它。

3 个答案:

答案 0 :(得分:7)

我遇到了同样的问题,并通过升级到Scala 2.12.6来解决了这个问题:

sudo apt remove scala-library scala
wget www.scala-lang.org/files/archive/scala-2.12.6.deb
sudo dpkg -i scala-2.12.6.deb

答案 1 :(得分:0)

通过为2.11.12版禁用fsc对我有用:

#!/usr/bin/env -S scala -nc

答案 2 :(得分:-2)

安装最新的scala 2.12.6 manualy(来自tar gz)现在一切正常,打印测试