HP HLM的CLR SQL触发器问题

时间:2018-06-15 11:46:15

标签: sql-server triggers alm

我编写了CLR SQL触发器来从数据库获取数据并使用rest api发布到其他网站。当我使用插入查询手动插入时,它正在工作。 但是我从HP ALM站点创建了缺陷我只得到了缺陷ID剩下的列就像空了。 请找到以下代码和

CREATE TRIGGER tri_Publishes_clr
ON td.BUG
for INSERT
AS 
      EXTERNAL NAME triggertestwebapi.CLRTrigger.showinserted

    CREATE ASSEMBLY   triggertestwebapi
FROM 'D:\hackthon\CLRTrigger\CLRTrigger\bin\Debug\CLRTrigger.dll'
WITH PERMISSION_SET = UNSAFE


    public static void showinserted()
    {
        SqlTriggerContext triggContext = SqlContext.TriggerContext;
        SqlConnection conn = new SqlConnection(" context connection =true ");
        conn.Open();
        SqlCommand sqlComm = conn.CreateCommand();
        SqlPipe sqlP = SqlContext.Pipe;
        SqlDataReader dr;
        sqlComm.CommandText = "SELECT BG_BUG_ID,BG_SUMMARY from inserted";
        dr = sqlComm.ExecuteReader();
        string postData=string.Empty;
        string comment = "User Story:23;24";
        while (dr.Read())
        {
           // sqlP.Send((string)dr[0]);//+ "," + (dr[1] = DBNull.Value) ? string.Empty : dr[1].ToString());
            comment = (dr[0]==DBNull.Value?string.Empty:dr[0].ToString())+(dr[1] == DBNull.Value ? "venkat" : dr[0].ToString());
            sqlP.Send(comment);
        }

先谢谢了, Venkat

0 个答案:

没有答案