我正在使用angular,我想在HTML中显示函数的结果。当我使用
#define _GNU_SOURCE
#include <stdio.h>
#include <string.h>
#include <errno.h>
#include <stddef.h>
#include <stdlib.h>
#define MAX_LINE_LENGTH 1024
void print_lines(FILE *stream) {
double a, b, c;
char line[MAX_LINE_LENGTH];
while (fgets(line, MAX_LINE_LENGTH, stream) != NULL) {
char *pnt;
// locate substring `<start>` in the line
if ((pnt = strstr(line, "<start>") != NULL)) {
// advance pnt to point to the characters after the `<start>`
pnt = &pnt[sizeof("<start>") - 1];
char *pntend;
// scan first number
a = strtod(pnt, &pntend);
if (pnt == pntend) {
fprintf(stderr, "Error converting a value.\n");
// well, handle error some better way than ignoring.
}
pnt = pntend;
// scan second number
b = strtod(pnt, &pntend);
if (pnt == pntend) {
fprintf(stderr, "Error converting a value.\n");
// well, handle error some better way than ignoring.
}
pnt = pntend;
// scan third number
c = strtod(pnt, &pntend);
if (pnt == pntend) {
fprintf(stderr, "Error converting a value.\n");
// well, handle error some better way than ignoring.
}
printf("Read values are %lf %lf %lf\n", a, b, c);
} else {
// normal line
//fputs(line, stdout);
}
}
}
int main()
{
print_lines(stdin);
return 0;
}
&#13;
HTML中的
然后是{{latlng}},它总是显示整个函数的代码,而不是返回值,即使我只是返回latlng值。我哪里错了?
查看问题: assign function return value to some variable using javascript
整个.ts文件:
var geo = function onLocationFound(e) {
var radius = e.accuracy / 2;
let marker = new L.Marker(e.latlng, {
draggable: true,
icon: Icon
}).bindPopup(""+e.latlng);;
map.addLayer(marker);
return e.latlng
}
this.latlng = geo;
&#13;
答案 0 :(得分:1)
您将函数本身分配给this.latlng
,而不是调用函数并分配结果。通过添加括号来调用该函数:
this.latlng = geo();
答案 1 :(得分:0)
尝试以下代码:
function onLocationFound(e) {
var radius = e.accuracy / 2;
let marker = new L.Marker(e.latlng, {
draggable: true,
icon: Icon
}).bindPopup(""+e.latlng);;
map.addLayer(marker);
this.latlng = e.latlng
}
}
在HTML中:
{{ latlng }}
如果你想把它传递到其他地方或其他函数,那么使用this.latlng作为函数参数