代码在本地服务器上工作但不适用于Go-daddy服务器

Question

在我的电脑上本地安装了php 7.2。 ＆安培;关于Godaddy PHP版本是7.4

那是一个带有mysql数据库的post webservice。我们需要从请求体传递id，它与表数据匹配，并以json对象的形式返回匹配行。

<?php

if ($_SERVER['REQUEST_METHOD'] == "POST") {

header('Content-type: application/json');

 $response = array();

// Create connection
    $conn = new mysqli($servername, $username, $password, $db);

    if (!isset($_POST['id'])) {

        $response['code'] = 0;
        $response['message'] = 'Please set AppID (id) before submit';

        echo json_encode($response);
    } else {

        $id = $_POST['id'];

// Check connection
        if ($conn->connect_error) {
            die("Connection failed: " . $conn->connect_error);
        }
//echo "Connected successfully";

        //$sql = "SELECT * FROM appdetails where `AppPackage` = '$id'";
        
        $sql = "SELECT * FROM appdetails where AppPackage = " . $id;

        $result = $conn->query($sql);

       
        if ($result->num_rows > 0) {

            $op = $result->fetch_all(MYSQLI_ASSOC);

            $op['error_code'] = 1;

            echo json_encode($op);
            
        } else {

            $response['code'] = 0;
            $response['message'] = 'AppID is not define.';

            echo json_encode($response);
        }
    }
} else {
    
    $response['code'] = 0;
    $response['message'] = 'Calling method is wrong.';

    echo json_encode($response);
}
?>