Question

我需要将项目列表转换为单个dto项目。如果列表中有任何元素，我们将采用第一个元素。我用这种方式实现了转换器接口，但它不起作用。转换后目标项为空。

public class LocationConverter implements Converter<List<Location>,LocationDto> {

@Override
public LocationDto convert(MappingContext<List<Location>, LocationDto> mappingContext) {
    ModelMapper modelMapper = new ModelMapper();
    List<Location> locations = mappingContext.getSource();
    LocationDto locationDto = mappingContext.getDestination();
    if (locations.size() >= 1) {
        Location location = locations.get(0);
        modelMapper.map(location, locationDto);
        return locationDto;
    }
    return null;
   }
}

 ModelMapper modelMapper = new ModelMapper();
 modelMapper.addConverter(new LocationConverter());
 Event event = new Event();
 modelMapper.map(event, eventDto);

我应用此转换器的实体看起来如此：

public class Event extends BasicEntity  {

  private Integer typeId;

  private String typeName;

  private List<Location> locationList;

}


public class EventDto {

    private Integer typeId;

   private String typeName;

   private LocationDto location;
}

所以我需要将Event中的位置列表转换为EventDto中的LocationDto。

Answer 1

我们可以为每个属性映射定义一个转换器，这意味着我们将locationList映射到具有自定义转换器的位置。

使用Java8

modelMapper.typeMap(Event.class, EventDto.class).addMappings(
        mapper -> mapper.using(new LocationConverter()).map(Event::getLocationList, EventDto::setLocation));

使用Java 6/7

modelMapper.addMappings(new PropertyMap() {
    @Override
    protected void configure() {
        using(new LocationConverter()).map().setLocation(source.getLocationList());
    }
});

将项列表转换为单个对象

1 个答案: